在javascript中将字节数组转换为字符串

问题描述

如何将字节数组转换为字符串？

我发现这些功能是相反的：

  function string2Bin（s）{
 var b = new Array（）; 
 var last = s.length; 
 
 for（var i = 0; i  var d = s.charCodeAt（i）; 
 if（d  b [i] = dec2Bin（d）; 
 else {
 var c = s.charAt（i）; 
 alert（c +'不是ASCII字符'）; 
 b [i] = -1; 
} 
} 
 return b; 
} 
 
函数dec2Bin（d）{
 var b =''; 
 
 for（var i = 0; i  b =（d％2）+ b; 
 d = Math.floor（d / 2）; 
} 
 
 return b; 
} 
  

但是如何使函数以其他方式工作？

谢谢。

Shao

解决方案>

您需要将每个八位字节解析为数字，并使用该值获取一个字符，如下所示：

  function bin2String（array）{
 var result =; 
 for（var i = 0; i  result + = String.fromCharCode（parseInt（array [i]，2））; 
} 
 return result; 
} 
 
 bin2String（[01100110，01101111，01101111]）; //foo
 
 //使用string2Bin函数来测试：
 bin2String（string2Bin（hello world））===hello world; 
  

编辑：是，您当前的 string2Bin 可以写得更快：

  function string2Bin（str）{
 var result = ]; 
 for（var i = 0; i  result.push（str.charCodeAt（i）.toString（2））; 
} 
 return result; 
} 
  

但是通过查看你链接的文档，我认为 setBytesParameter 方法期望blob数组包含十进制数，而不是位字符串，因此您可以这样写：

 函数string2Bin（str）{
 var result = []; 
 for（var i = 0; i  result.push（str.charCodeAt（i））; 
} 
 return result; 
} 
 
函数bin2String（array）{
 return String.fromCharCode.apply（String，array）; 
} 
 
 string2Bin（'foo'）; // [102，111，111] 
 bin2String（string2Bin（'foo'））==='foo'; // true 
  

How do I convert a byte array into a string?

I have found these functions that do the reverse:

function string2Bin(s) {
    var b = new Array();
    var last = s.length;

    for (var i = 0; i < last; i++) {
        var d = s.charCodeAt(i);
        if (d < 128)
            b[i] = dec2Bin(d);
        else {
            var c = s.charAt(i);
            alert(c + ' is NOT an ASCII character');
            b[i] = -1;
        }
    }
    return b;
}

function dec2Bin(d) {
    var b = '';

    for (var i = 0; i < 8; i++) {
        b = (d%2) + b;
        d = Math.floor(d/2);
    }

    return b;
}

But how do I get the functions working the other way?

Thanks.

Shao

解决方案

You need to parse each octet back to number, and use that value to get a character, something like this:

function bin2String(array) {
  var result = "";
  for (var i = 0; i < array.length; i++) {
    result += String.fromCharCode(parseInt(array[i], 2));
  }
  return result;
}

bin2String(["01100110", "01101111", "01101111"]); // "foo"

// Using your string2Bin function to test:
bin2String(string2Bin("hello world")) === "hello world";

Edit: Yes, your current string2Bin can be written more shortly:

function string2Bin(str) {
  var result = [];
  for (var i = 0; i < str.length; i++) {
    result.push(str.charCodeAt(i).toString(2));
  }
  return result;
}

But by looking at the documentation you linked, I think that the setBytesParameter method expects that the blob array contains the decimal numbers, not a bit string, so you could write something like this:

function string2Bin(str) {
  var result = [];
  for (var i = 0; i < str.length; i++) {
    result.push(str.charCodeAt(i));
  }
  return result;
}

function bin2String(array) {
  return String.fromCharCode.apply(String, array);
}

string2Bin('foo'); // [102, 111, 111]
bin2String(string2Bin('foo')) === 'foo'; // true

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