从字符串中提取网址

问题描述

我有一个网址:

url = "http://timesofindia.feedsportal.com/fy/8at2EuL0ihSIb3s7/story01.htmA"

末尾有一些不需要的字符，例如 A,TRE.我想删除它，所以 URL 将是这样的:

There are some unwanted characters like A,TRE, at the end. I want to remove this so the URL will be like this:

url = http://timesofindia.feedsportal.com/fy/8at2EuL0ihSIb3s7/story01.htm

如何删除它们?

推荐答案

如果你的 url 总是以 .htm、.apsx 或 .php 结尾代码>你可以用一个简单的正则表达式来解决它:

If your url always finish with .htm, .apsx or .php you can solve it with a simple regex:

url = url[/^(.+\.(htm|aspx|php))(:?.*)$/, 1]

测试在Rubular这里.

首先我使用 此方法 获取子字符串，类似于切片.然后是正则表达式.从左到右:

First I use this method to get a substring, works like slice. Then comes the regex. From left to right:

^                   # Start of line
  (                   # Capture everything wanted enclosed
    .+                  # 1 or more of any character
    \.                  # With a dot after it
    (htm|aspx|php)      # htm or aspx or php
  )                   # Close url asked in question
  (                   # Capture undesirable part
    :?                  # Optional
    .*                  # 0 or more any character
  )                   # Close undesirable part
$                   # End of line

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