jQuery的未确认前$在jqGrid的dataUrl方法P $ pssion错误edittype ='选择'

问题描述

这是在<延续href=\"http://stackoverflow.com/questions/30981085/how-to-pass-parameter-to-editoptions-dataurl-method-for-edittype-select-for-in/30981678?noredirect=1#comment50022434_30981678\">this线。我使用的自由的jqGrid 4.9.0 并有内联编辑。

  {名称：'联系人姓名'，可编辑：真，宽度：100，排序：假的，冷冻的：真实，格式：'选择'，edittype：'选择'，
                    editoptions：{
                        dataUrl：'/ InvestorList / GetContactList'，
                        POSTDATA：功能（ROWID，价值，cmName）{                            返回{专案编号：ROWID};
                        }
                    }
 

在我的ASP.NET MVC的控制器，我有以下方式：

 公共JsonResult GetContactList（字符串专案编号）
    {
        VAR接触=新的解释和LT;字符串，字符串＆GT;（）; // context.GetContactList（专案编号）;
        contacts.Add（123，IAM1）;
        contacts.Add（1234，IAM2）;
        contacts.Add（12345，IAM3）;
        返回JSON（联系人，JsonRequestBehavior.AllowGet）;
    }
 

使用IE浏览器的开发者工具，这是响应：

  {123：IAM1，1234：IAM2，12345：IAM3}
 

不过，我得到以下错误，

I'm wondering what kind of format does dataUrl expect because I use the exact same format for other columns e.g. editoptions: { value: TeaserStatusList } In this case TeaserStatusList has the same format as {"123":"IAM1","1234":"IAM2","12345":"IAM3"}

Thanks

Update:

{ name: 'ContactId', editable: true, width: 100, sortable: false, edittype: 'select', editoptions: {  dataUrl: '/InvestorList/GetContactList',
                        postData: function (rowid, value, cmName) {                            
                            var accid = $(gridId).jqGrid("getCell", rowid, "AccountId");
                            return { accountId: accid };
                        },
                        buildSelect: function (data) {
                            var s = "<select>";
                            data = JSON.parse(data);
                            $.each(data, function (k, v) {
                                s += '<option value="' + k + '">' + v + '</option>';
                            });
                            return s + "</select>";
                        }
                    }

解决方案

jqGrid expect that dataUrl returns HTML fragment with <select> statement. Thus you should add buildSelect property in editoptions which converts the server response to the string with <select> statement. The corresponding code could be something like below

buildSelect: function (data) {
     var s = "<select>", i, l, val;
     if (data != null) {
         for (val in data) {
             if (data.hasOwnProperty(val)) {
                 s += "<option value='" + val + "'>" + data[val] + "</option>";
             }
         }
     }
     return s + "</select>";
 }

I didn't tested the code, but it seems to me it corresponds the format of data returned from GetContactList action.

I would recommend you to add the line HttpContext.Current.Response.Cache.SetMaxAge (new TimeSpan(0)); at the begining of the action GetContactList to be sure that you will have no problem with caching and the action GetContactList will be called every time.

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