问题描述
install.packages('RCurl')
require(RCurl)
install.packages('zoo')
require(zoo)
x = getURL("https://raw.githubusercontent.com/RInterested/DATASETS/gh-pages/interest%20in%20soccer%20in%20the%20US.csv")
soccer <- read.csv(textConnection(x), header=T)
s <- zoo(soccer)
plot.ts(s$soccer_US)
结果
但我需要 x 轴作为日期.
but I need the x-axis to be the dates.
我知道有很多关于同一主题的帖子，尽管其中很多——包括我可能发布的一些——都包含 xaxt=n"，这似乎是一个非常绕道而行.
I know there are a good number of posts on the same topic, although many of them - including some I might have posted - entail xaxt="n", which seems to be a very circuitous way to go about it.
在基本的 plot() 中是否有更简单的方法来保留 x 轴的日期结构?
Is there a simpler way of preserving the date structure of the x axis in basic plot()?
推荐答案
在问题的代码中，zoo(...) 命令使用不正确.请参阅 ?zoo 以获取有关它的信息.
In the code in the question the zoo(...) command is used incorrectly. See ?zoo to get information on it.
为此，使用 yearmon 类将文件读入动物园对象 z，然后使用 plot 或 autoplot.
To do this read the file into a zoo object, z, using yearmon class for the times and then just use plot or autoplot.
library(zoo)
u <- "https://raw.githubusercontent.com/RInterested/DATASETS/gh-pages/interest%20in%20soccer%20in%20the%20US.csv"
z <- read.csv.zoo(u, FUN = as.yearmon)
plot(z)
或将最后一行替换为:
library(ggplot2)
autoplot(z) + scale_x_yearmon()
注意
文件的前几行如下所示:
Note
The first few lines of the file look like this:
L <- readLines(u)
writeLines(head(L))
给予:
date,count
2004-01,25
2004-02,29
2004-03,33
2004-04,36
2004-05,37
这篇关于在基本 R plot() 中显示时间序列日期结构的自动方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！