问题描述
我已经从Antlr 3升级到Antlr 4.我使用这个代码来捕获异常使用这个代码。但这不适用于Antlr 4.
I have upgraded from Antlr 3 to Antlr 4. I was using this code to catch exceptions using this code. But this is not working for Antlr 4.
partial class XParser
{
public override void ReportError(RecognitionException e)
{
base.ReportError(e);
Console.WriteLine("Error in Parser at line " + ":" + e.OffendingToken.Column + e.OffendingToken.Line + e.Message);
}
}
这是出现的错误
'Parser.ReportError(Antlr4.Runtime.RecognitionException)': no suitable method found to override
在Antlr 4中,在输入流中发生的累积错误的预期方式是什么。我无法找到一种方法来实现这个在网上。请提供一些指导。
In Antlr 4 what is the expected way of accumulating errors that occurs in the input stream. I was unable to find a way to achieve this on the net. Please provide me some guidelines.
编辑:
我已经实现了XParser如下
I have implemented the XParser as below
partial class XParser : IAntlrErrorListener<IToken>
{
public void SyntaxError(IRecognizer recognizer, IToken offendingSymbol, int line, int charPositionInLine, string msg, RecognitionException e)
{
Console.WriteLine("Error in parser at line " + ":" + e.OffendingToken.Column + e.OffendingToken.Line + e.Message);
}
}
正如你所说的,我可以使用任何的上述类。但是我无法注册这个侦听器,在主程序中,我混淆了作为侦听器
的传递参数。请帮助我注册。
As you said I can extend this parser class using any of the mentioned classes. But I was unable to register this listener, in the main program I am confused with passing argument as the listener
. Please help me with the registering.
我可以看到,这些类有能力产生更有意义的错误消息,不是吗?
As I can see these classes has the capability of producing more meaningful error messages don't they?
推荐答案
您需要实施。如果你想要的是报告错误,像你有以上,那么你应该关注 SyntaxError
方法。
ConsoleErrorListener
BaseErrorListener
DiagnosticErrorListener
错误侦听器通过调用 parser.AddErrorListener(listener)
。
编辑:您需要创建一个新类,错误侦听器接口。然后将侦听器附加到解析器。解析器本身不会实现错误侦听器接口。
You need to create a new class which implements the error listener interface. You then attach the listener to the parser. The parser itself will not implement the error listener interface.
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