问题描述
我正在尝试让我的头正确地围绕CSS3渐变(特别是径向渐变),在这样做,我认为我已经给自己一个相对艰难的挑战。
在Adobe Illustrator中,我创建了以下按钮样式。
要创建这个图片,我创建了一个背景颜色为 rgb(63,64 ,63)
或#3F403F
,然后将其风格化为15px的边框半径。
$ b b然后,我用一个25%的不透明度,8px模糊,从中心白色的内部发光。最后,我应用了3pt白色笔画。 (我告诉你所有这一切,如果你想重现它,如果上面的图像是不够的。)
所以,我的问题是: / p>
是否可以使用CSS重新创建此按钮,而无需使用图片?
我知道Internet Explorer的限制(为了这个实验,我不能给猴子)。我也知道webkit中的一个小的错误,它错误地呈现了一个背景颜色,边框半径和边框(与背景颜色不同的颜色)的元素 - 它让背景颜色在弯曲
到目前为止,我最好的尝试是相当可悲的,但这里的代码是:
section#featured footer pa
{
color:rgb(255,255,255);
text-shadow:1px 1px 1px rgba(0,0,0,0.6);
text-decoration:none;
padding:5px 10px;
border-radius:15px;
-moz-border-radius:15px;
-webkit-border-radius:15px;
border:3px solid rgb(255,255,255);
background:rgb(98,99,100);
background:-moz-radial-gradient(
50%50%,
farthest-side,
#626364,
#545454
);
background:-webkit-gradient(
radial,
50%50%,
1px,
50%50%,
5px,
from(rgb(98,99,100)),
to(rgb(84,84,84))
);
}
基本上,可怕。
似乎你正在尝试生产一个渐变来复制这个:
您可以使用插图盒阴影来做到这一点。例如:
-moz-box-shadow:inset 0 0 8px rgba(0,0,0,0.25);
-webkit-box-shadow:inset 0 0 8px rgba(0,0,0,0.25);
I am in the process of trying to get my head properly around CSS3 Gradients (specifically radial ones) and in doing so I think I've set myself a relatively tough challenge.
In Adobe Illustrator I have created the following 'button' style.
To create this image I created a rectangle with a background colour of rgb(63,64,63)
or #3F403F
, then 'stylized' it to have a 15px border radius.
I then applied an 'inner glow' to it with a 25% opacity, 8px blur, white from the center. Finally, I applied a 3pt white stroke on it. (I'm telling you all of this in case you wished to reproduce it, if the image above isn't sufficient.)
So, my question is thus:
Is it possible to recreate this 'button' using CSS without the need for an image?
I am aware of the 'limitations' of Internet Explorer (and for the sake of this experiment, I couldn't give a monkeys). I am also aware of the small 'bug' in webkit which incorrectly renders an element with a background colour, border-radius and a border (with a different color to the background-color) - it lets the background color bleed through on the curved corners.
My best attempt so far is fairly pathetic, but for reference here is the code:
section#featured footer p a
{
color: rgb(255,255,255);
text-shadow: 1px 1px 1px rgba(0,0,0,0.6);
text-decoration: none;
padding: 5px 10px;
border-radius: 15px;
-moz-border-radius: 15px;
-webkit-border-radius: 15px;
border: 3px solid rgb(255,255,255);
background: rgb(98,99,100);
background: -moz-radial-gradient(
50% 50%,
farthest-side,
#626364,
#545454
);
background: -webkit-gradient(
radial,
50% 50%,
1px,
50% 50%,
5px,
from(rgb(98,99,100)),
to(rgb(84,84,84))
);
}
Basically, terrible. Any hints or tips gratefully accepted and thank you very much in advance for them!
It seems like you're trying to produce a gradient to replicate this:
You can do exactly that using an inset box-shadow. For example:
-moz-box-shadow: inset 0 0 8px rgba(0,0,0, 0.25);
-webkit-box-shadow: inset 0 0 8px rgba(0,0,0, 0.25);
这篇关于CSS3渐变从应用了边框半径的Illustrator重现“内部发光”效果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!