问题描述
我在需要一些文件时遇到了问题,PHP告诉我这些文件不存在,但是当我扫描目录时会告诉我它确实存在.
I've got a problem with requiring some files, PHP is telling me these files do not exist, but when I scan the directory it tells me it does exist.
我已将文件简化为require
功能,但仍无法正常工作.
I've simplified the files to the require
functionality, and it's still not working.
这是我的设置:
root/
test.php
test/
test2.php
sub/
test3.php
test.php
echo 'test';
require 'test/sub/test3.php';
test/test2.php (由于某种原因未包含该文件)
test/test2.php (the file that for some reason doesn't get included)
echo 'test2';
test/sub/test3.php
echo 'test3';
/*
because we are still on test.php, the include path is the root
that means the following would work:
require 'test/test2.php';
however I don't know this path in this file. (it's dynamic)
I thought this would work:
*/
set_include_path(dirname(__FILE__));
require '../test2.php';
编辑
好的,当我更改此设置时:
Okay, when I changed this:
set_include_path(dirname(__FILE__));
require '../test2.php';
到
set_include_path(dirname(__FILE__)."/../"));
require 'test2.php';
有效. wtf php吗?
it works. wtf php?
现在这是我的输出:
testtest3
Warning: require(../test2.php) [function.require]: failed to open stream: No such file or directory in siteroot/test/sub/test3.php on line 6
Fatal error: require() [function.require]: Failed opening required '../test2.php' (include_path='siteroot/test/sub') in siteroot/test/sub/test3.php on line 6
如果我将以下代码添加到test3.php
:
If I add the following code to test3.php
:
echo '<pre>';
print_r(scandir(dirname(__FILE__).'/../'));
echo '</pre>';
(预期)我得到以下信息:
I get (as expected) the following:
Array
(
[0] => .
[1] => ..
[2] => sub
[3] => test2.php
)
我想我快要疯了,当我读到错误时,似乎PHP告诉我一个文件不存在,确切地在文件所在的位置. >
I think I'm going insane, when I read the errors it looks to me like PHP is telling me a file doesn't exist, exactly in the place where the file is.
推荐答案
更改
set_include_path(dirname(__FILE__));
require '../test2.php';
到
set_include_path(dirname(__FILE__)."/../");
require 'test2.php';
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