本文介绍了如何在C#4.0中删除指定xmlnode的所有子节点?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的xml。
<Document>
<page no="1">
<Paragraph no="1">
<Line>line1</Line>
</Paragraph>
<Paragraph no="2">
<Line>line2</Line>
</Paragraph>
</page>
<page no="2">
<Paragraph no="1">
<Line>line1</Line>
</Paragraph>
<Paragraph no="2">
<Line>line2</Line>
</Paragraph>
</page>
</Document>
我的C#代码是
XmlDocument xd = new XmlDocument();
xd.Load(@"H:\Sample-8-final.xml");
XmlNodeList pnodelist = xd.GetElementsByTagName("page");
XmlNodeList xdChildNodeList = xd.ChildNodes;
for (int i = 0; i < pnodelist.Count; i++)
{
XmlNode pageNode = pnodelist[i];
foreach (XmlNode xxNode in pageNode.ChildNodes)
{
if (xxNode.Name.ToString().Trim().Equals("Paragraph"))
{
foreach (XmlNode yyNode in xxNode.ChildNodes)
{
yyNode.ParentNode.RemoveChild(yyNode);
}
}
}
xd.Save(@"H:\Sample-8-final_1.xml");
我的必需输出为
<Document>
<page no="1">
<Paragraph no="1">
</Paragraph>
<Paragraph no="2">
</Paragraph>
</page>
<page no="2">
<Paragraph no="1">
</Paragraph>
<Paragraph no="2">
</Paragraph>
</page>
</Document>
但是我的代码产生了如下错误的结果:
but my code produced wrong result like below:
<Document>
<page no="1">
<Paragraph no="1">
</Paragraph>
<Paragraph no="2">
<Line>line2</Line>
</Paragraph>
</page>
<page no="2">
<Paragraph no="1">
</Paragraph>
<Paragraph no="2">
<Line>line2</Line>
</Paragraph>
</page>
</Document>
请引导我摆脱此问题...
Please Guide me to get out of this issue...
推荐答案
使用LINQ to XML删除Paragraph元素的所有后代:
Use LINQ to XML to remove all descendants of the Paragraph elements:
XElement root = XElement.Load(@"H:\Sample-8-final_1.xml");
root.Descendants("Paragraph").Descendants().Remove();
注意:您需要使用System.Xml.Linq放入;
在文件顶部。
Note: you need to put using System.Xml.Linq;
at the top of your file.
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