本文介绍了在bash中格式化和组合xpath的输出的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用 bash 实用程序 xpath
解析此 xml 输入:
I'm trying to parse this xml input using the bash utility xpath
:
<?xml version="1.0" encoding="UTF-8"?>
<feed version="0.3" xmlns="http://purl.org/atom/ns#">
<entry>
<title>Title 1</title>
<author>Author 1</author>
</entry>
<entry>
<title>Title 2</title>
<author>Author 2</author>
</entry>
</feed>
我需要这种格式的输出:
I need an output in this format:
1. Title: Title 1
Author: Author 1
2. Title: Title 2
Author: Author 2
为了以简单的方式(仅使用一个 xpath
命令或最多 3-4 个命令)实现这一目标,我做了很多尝试,但我所有的努力都白费了.有人可以帮我解决这个问题吗?
I've fiddled around a lot trying to achieve this in a simple way (using only a single xpath
command, or at most 3-4 commands), but all my efforts have been in vain. Could anyone please help me out with this?
推荐答案
Bash 版本
#!/bin/bash
count=1
input=input.xml
while [ -n "$title" -o $count = 1 ]
do
title=`cat $input | xpath //entry[$count]/title 2>/dev/null | sed s/<title>//g| sed s/<\\/title>//g`
author=`cat $input | xpath //entry[$count]/author 2>/dev/null | sed s/<author>//g| sed s/<\\/author>//g`
if [ "$title" -a "$author" ]; then
echo $count $title $author
fi
count=$((count+1))
done
Perl 版本(未经测试)...
Perl version (untested) ...
#!/usr/bin/perl
use XML::XPath;
my $file = 'input.xml';
my $xp = XML::XPath->new(filename => $file);
my $count = 1;
foreach my $entry ($xp->find('//entry')->get_nodelist){
print $count;
print 'Title:' . $entry->find('title')->string_value;
print 'Author: ' . $entry->find('author');
$count++;
}
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