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问题描述
在BASH中,是否可以在函数主体中获得函数名称?以下面的代码为例,我想在其主体中打印函数名称"Test",但"$ 0"似乎是指脚本名称而不是函数名称.那么如何获得函数名称呢?
In BASH, is it possible to get the function name in function body? Taking following codes as example, I want to print the function name "Test" in its body, but "$0" seems to refer to the script name instead of the function name. So how to get the function name?
#!/bin/bash
function Test
{
if [ $# -lt 1 ]
then
# how to get the function name here?
echo "$0 num" 1>&2
exit 1
fi
local num="${1}"
echo "${num}"
}
# the correct function
Test 100
# missing argument, the function should exit with error
Test
exit 0
推荐答案
尝试 $ {FUNCNAME [0]}
.该数组包含当前的调用堆栈.引用手册页:
Try ${FUNCNAME[0]}
. This array contains the current call stack. To quote the man page:
FUNCNAME
An array variable containing the names of all shell functions
currently in the execution call stack. The element with index 0
is the name of any currently-executing shell function. The bot‐
tom-most element is "main". This variable exists only when a
shell function is executing. Assignments to FUNCNAME have no
effect and return an error status. If FUNCNAME is unset, it
loses its special properties, even if it is subsequently reset.
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