错误：“;”之前的预期构造函数，析构函数或类型转换令牌？

问题描述

我正在尝试编译我的代码以测试读取和打印数据文件的功能，但是我收到了一个我不理解的编译错误-错误：'之前的预期构造函数，析构函数或类型转换； '令牌。

I'm trying to compile my code to test a function to read and print a data file, but I get a compiling error that I don't understand - "error: expected constructor, destructor, or type conversion before ';' token". Wall of relevant code-text is below.

struct Day
{
  int DayNum;
  int TempMax;
  int TempMin;
  double Precip;
  int TempRange;
};

struct Month
{
  Day Days[31];
  int MonthMaxTemp;
  int MonthMinTemp;
  double TotalPrecip;
  int MonthMaxTempRange;
  int MonthMinTempRange;
  double AverageMaxTemp;
  double AverageMinTemp;
  int RainyDays;
  double AveragePrecip;
}theMonth;

double GetMonth();

double GetMonth()
{
  for (int Today = 1; Today < 31; Today++)
    {
      cout << theMonth.Days[Today].TempMax << theMonth.Days[Today].TempMin;
      cout << theMonth.Days[Today].Precip;
    }
  return 0;
}

GetMonth();  // compile error reported here

推荐答案

出现错误的行看起来您正在尝试调用GetMonth，但是在全局级别，一个C ++程序由一系列声明组成。由于函数调用不是声明，因此不能在全局级别孤立存在。您可以有一个声明，该声明也是一个定义，在这种情况下，它可以调用函数作为初始化的一部分。

The line with the error looks like you're trying to call GetMonth -- but at the global level, a C++ program consists of a series of declarations. Since a function call isn't a declaration, it can't exist in isolation at the global level. You can have a declaration that's also a definition, in which case it can invoke a function as part of initialization.

一个函数调用本身必须包含在其他函数中：

A function call by itself, however, has to be contained within some other function:

#ifdef TEST
int main() { 
    GetMonth();
}
#endif

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