问题描述
当我处理print()函数(Python 3)时出现问题.
There is a problem when i deal with print() function(Python 3).
当我寻找序列的总和时，我可以使用以下代码模式:
When I'm looking for sum of a series I may use the following code pattern:
>>> sum(i for i in range(101))
但是当我倾向于检查自己制作的系列时:(我选择print()并假设它将逐行打印出来)
But when I tend to check the series that I had made: (I choose print() and assume it will print out line by line)
>>> print(i for i in range(101))
原来变成了没有值返回的生成器对象.因此，我必须使用list()进行序列检查.那是打印功能上的缺陷吗?
It turns out become a generator object without value return. So I have to used list() for series checking. Is that a flaw in print function?
PS:以上内容是构成生成器的示例，不是自然序列的最简单形式，而是复杂序列的骨骼结构.为了方便进行系列值检查，我正在寻找一种逐行打印每个值的方法.
PS: The above written is an example to form a generator, not the simplest form for natural series but the bone structure for complex series. In order for convenience in series values checking, I am looking for a way to print out each value line by line.
推荐答案
sum需要进行一系列迭代处理，而print需要单独的参数进行打印.如果要将生成器的所有项目分别喂入print，请使用*表示法:
sum takes an iterable of things to add up, while print takes separate arguments to print. If you want to feed all the generator's items to print separately, use * notation:
print(*(i for i in range(1, 101)))
不过，无论哪种情况，您实际上都不需要生成器:
You don't actually need the generator in either case, though:
sum(range(1, 101))
print(*range(1, 101))
如果希望将它们放在单独的行上，则表示您希望多次调用print的行为，这意味着您希望看到规则循环的行为:
If you want them on separate lines, you're expecting the behavior of multiple individual calls to print, which means you're expecting the behavior of a regular loop:
for item in generator_or_range_or_whatever:
print(item)
尽管您还可以选择将'\n'指定为项目分隔符:
though you also have the option of specifying '\n' as an item separator:
print(*generator_or_range_or_whatever, sep='\n')
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