urllib挂起

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本文介绍了urllib挂起的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是我的代码的基本版本


为网址​​中的网址:

fp = urllib.urlopen(url)

lines = fp.readlines()


#print lines

for line in lines:

#print line

if(reUrl.search(line)):

打印''找到''

返回1

else:

打印''找不到''

返回0


偶尔挂起某些网址。如果我执行ctrl-c

(linux),它将转到下一个url。我如何才能暂停

并转到下一个网址。

This is a basic version of my code

for url in urls:
fp = urllib.urlopen(url)
lines = fp.readlines()

#print lines
for line in lines:
#print line
if(reUrl.search(line)):
print ''found''
return 1
else:
print ''not found''
return 0

this hangs occasionally for some certain url''s. If I do a ctrl-c
(linux) it will move on to the next url. How can I get this to timeout
and move on to the next url.

推荐答案



自2.3以来有socket.setdefaulttimeout(),这应该是作业:


导入套接字

socket.setdefaulttimeout(10)

#10s后抛出socket.timeout异常,

#默认是无限期等待(或至少非常非常长的时间......)


对于较旧的python版本,请谷歌搜索timeoutsocket.py


since 2.3 there''s socket.setdefaulttimeout(), this should to the job:

import socket
socket.setdefaulttimeout(10)
# throw socket.timeout exception after 10s,
# default is to wait a infinitly (or at least a very, very long time...)

For older python versions, ask google for timeoutsocket.py









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07-20 16:15
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