多维数组，我怎么能检查所有相邻瓷砖了在边界某些细胞？

问题描述

我创建了一个12×12格，这网格内我创建'传染'的瓷砖，当一个受感染的瓷砖是由其他被感染的瓷砖包围，包围细胞变成患病瓦。我在想，如果有检查相邻的一个很好的方式在边界细胞的价值？

公共静态无效diseaseTiles（）{
    INT I，J;
    对于（i = 0; I＆LT; 12;我++）{
        为（J = 0; J＆LT; 12; J ++）{
            如果（myGrid [I] [J] =='我'）{
                INT左，右，上，下​​;
                如果（我== 0）{
                    左= 1;
                }
                如果（我== 11）{
                    右= 1;
                }
                如果（J == 0）{
                    向上= 1;
                }
                如果（J == 11）{
                    向下= 1;
                }
                //这是我已经得到了被困
                //我要使用上述廉政局的决定
                //是否在该方向上相邻的瓦片
                //应检查（他们网格的边界）
            }
        }
    }
}


解决方案

您可以检查单元格被采取短路评价的优势感染：

 布尔leftInfected =（I = 0！）及和放大器; myGrid [I-1] [J] =='我';
布尔rightInfected =＆AMP（I = 11！）;＆安培; myGrid [I + 1] [J] =='我';
布尔topInfected =（J = 0！）及＆放大器; myGrid [I] [J-1] =='我';
布尔bottomInfected =（J = 11！）及＆放大器; myGrid [I] [J + 1] =='我';
 

在这之后，你可以检查所有四个被感染：

 如果（leftInfected＆安培;＆安培; rightInfected和放大器;＆安培; topInfected和放大器;＆安培; bottomInfected）{
    myGrid [I] [J] ='D';
}
 

I've created a 12x12 grid, and within this grid I have created 'infected' tiles, when one infected tile is surrounded by other infected tiles, the surrounded cell becomes a diseased tile. I was wondering if there was a nice way of checking adjacent, in bounds cells for their value?

public static void diseaseTiles() {
    int i, j;
    for(i = 0; i < 12; i++) {
        for(j = 0; j < 12; j++) {
            if(myGrid[i][j] == 'I'){
                int left, right, up, down;
                if(i == 0) {
                    left = 1;
                }
                if(i == 11) {
                    right = 1;
                }
                if(j == 0) {
                    up = 1;
                }
                if(j == 11) {
                    down = 1;
                }
                //this is where I've gotten stuck
                //I was going to use the above int's to determine
                //whether or not the adjacent tile in that direction
                //should be checked (they're the border of the grid)
            }
        }
    }
}

解决方案

You can check if a cell is infected by taking advantage of short-circuited evaluation:

boolean leftInfected = (i!=0) && myGrid[i-1][j]=='I';
boolean rightInfected = (i!=11) && myGrid[i+1][j]=='I';
boolean topInfected = (j!=0) && myGrid[i][j-1]=='I';
boolean bottomInfected = (j!=11) && myGrid[i][j+1]=='I';

After that, you could check if all four are infected:

if (leftInfected && rightInfected && topInfected && bottomInfected) {
    myGrid[i][j] = 'D';
}

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