本文介绍了创建动态对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何动态地创建对象?
string[] columnNames = { "EmpName", "EmpID", "PhoneNo" };
List<string[]> columnValues = new List<string[]>();
for (int i = 0; i < 10; i++)
{
columnValues.Add(new[] { "Ramesh", "12345", "12345" });
}
List<Dictionary<string, object>> testData = new List<Dictionary<string, object>>();
foreach (string[] columnValue in columnValues)
{
Dictionary<string, object> data = new Dictionary<string, object>();
for (int j = 0; j < columnNames.Count(); j++)
{
data.Add(columnNames[j], columnValues[j]);
}
testData.Add(data);
}
虚类(类不在code可用):
class Employee
{
string EmpName { get;set; }
string EmpID { get;set; }
string PhoneNo { get;set; }
}
注意:属性/列名是动态的,
Note: Property/column names are dynamic.
现在我要转换的名单,其中,字典&LT;字符串,对象&gt;&GT;
类类型的名单,其中,对象&gt;
(IE)名单,其中,员工和GT;
Now I want to convert the List<Dictionary<string, object>>
to a class of type List<object>
(i.e) List<Employee>
.
是否有可能?建议请。
推荐答案
使用匿名对象(如果你知道的属性要投影):
Using an anonymous object (if you know the properties you want to project):
var employees =
(from dict in testData
select new
{
EmpName = dict["EmpName"] as string,
EmpID= dict["EmpID"] as string,
PhoneNo=dict["PhoneNo"] as string
}).ToList();
或者,使用Expando的(如果你需要动态地预测未知的列名):
Or, using Expando (if you need to dynamically project unknown column names):
string[] columnNames = { "EmpName", "EmpID", "PhoneNo" };
List<string[]> columnValues = new List<string[]>();
for (int i = 0; i < 10; i++)
{
columnValues.Add(new[] { "Ramesh", "12345", "12345" });
}
var testData = new List<ExpandoObject>();
foreach (string[] columnValue in columnValues)
{
dynamic data = new ExpandoObject();
for (int j = 0; j < columnNames.Count(); j++)
{
((IDictionary<String,Object>)data).Add(columnNames[j], columnValue[j]);
}
testData.Add(data);
}
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