使用 Objective-C/Cocoa 启动 Mac 应用程序

问题描述

使用命令行启动路径查找器应用程序时，我使用 open -a Path Finder.app/Users/.基于这个想法，我使用下面的代码来启动Path Finder.

When launching Path Finder app with command line, I use open -a Path Finder.app /Users/.Based on this idea, I use the following code to launch Path Finder.

我可以在不使用 open 命令行的情况下启动应用程序吗?

Can I have launch app without using open command line?

NSTask *task;
task = [[NSTask alloc] init];
[task setLaunchPath: @"/usr/bin/open"];

NSArray *arguments;
arguments = [NSArray arrayWithObjects: @"-a", @"Path Finder.app", @"/Users/", nil];
[task setArguments: arguments];

NSPipe *pipe;
pipe = [NSPipe pipe];
[task setStandardOutput: pipe];

NSFileHandle *file;
file = [pipe fileHandleForReading];

[task launch];

推荐答案

if(![[NSWorkspace sharedWorkspace] launchApplication:@"Path Finder"])
    NSLog(@"Path Finder failed to launch");

带参数:

NSWorkspace *workspace = [NSWorkspace sharedWorkspace];
NSURL *url = [NSURL fileURLWithPath:[workspace fullPathForApplication:@"Path Finder"]];
//Handle url==nil
NSError *error = nil;
NSArray *arguments = [NSArray arrayWithObjects:@"Argument1", @"Argument2", nil];
[workspace launchApplicationAtURL:url options:0 configuration:[NSDictionary dictionaryWithObject:arguments forKey:NSWorkspaceLaunchConfigurationArguments] error:&error];
//Handle error

你也可以使用 NSTask 来传递参数:

You could also use NSTask to pass arguments:

NSTask *task = [[NSTask alloc] init];
NSBundle *bundle = [NSBundle bundleWithPath:[[NSWorkspace sharedWorkspace] fullPathForApplication:@"Path Finder"]]];
[task setLaunchPath:[bundle executablePath]];
NSArray *arguments = [NSArray arrayWithObjects:@"Argument1", @"Argument2", nil];
[task setArguments:arguments];
[task launch];

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