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问题描述
我想做这样的事情:
const
MyFirstConstArray: array[0..1] of string = ('Hi', 'Foo');
MySecondConstArrayWhichIncludesTheFirstOne: array[0..2] of string =
MyFirstConstArray + ('Bar');
基本上我想要以下结果:
Basically I want the following result:
MyFirstConstArray -> ('Hi', 'Foo');
MySecondConstArrayWhichIncludesTheFirstOne -> ('Hi', 'Foo', 'Bar');
有可能吗?
推荐答案
AFAIK,您不能这样做。
但是,如果目标是确保只声明一次实际的常量字符串,建议您声明各个字符串,然后将它们分组为数组:
AFAIK, you can't do that.
But if the goal is to ensure you declare your actual constant string only once, I suggest you declare the individual strings and then group them in arrays:
const
MyConst1 = 'Hi';
MyConst2 = 'Foo';
MyConst3 = 'Bar';
MyFirstConstArray: array[0..1] of string = (MyConst1, MyConst2);
MySecondConstArrayWhichIncludesTheFirstOne: array[0..2] of string =
(MyConst1, MyConst2, MyConst3);
BTW,您的语法不正确,必须精确调整数组元素的类型。
BTW, your syntax is incorrect, you have to precise the type of the array elements.
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