批处理文件删除文本文件的前 3 行

问题描述

正如标题所述，我需要一个批处理文件来删除文本文件的前 3 行.

As the title states I need a batch file to delete the FIRST 3 lines of a text file.

例如:

A
B
C
D
E
F
G

在本例中，我需要将 A、B 和 C 与行一起删除

in this example I need A,B and C deleted along with the line

推荐答案

应该这样做

for /f "skip=3 delims=*" %%a in (C:file.txt) do (
echo %%a >>C:
ewfile.txt
)
xcopy C:
ewfile.txt C:file.txt /y
del C:
ewfile.txt /f /q

这将重新创建文件并删除前 3 行.

That will re-create the file with the first 3 lines removed.

为了让用户保持最新状态，您可以在批处理文件中以 vbscript 样式集成消息或在命令提示符中输出消息.

To keep the user updated you could integrate messages in the batch file in vbscript style or output messages in the command prompt.

@echo off
echo Removing...
for /f "skip=3 delims=*" %%a in (C:file.txt) do (
echo %%a >>C:
ewfile.txt
) >nul
echo Lines removed, rebuilding file...
xcopy C:
ewfile.txt C:file.txt /y >nul
echo File rebuilt, removing temporary files
del C:
ewfile.txt /f /q >nul
msg * Done!
exit >nul

希望这会有所帮助.

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