问题描述
我正在尝试使用zipfile在Python上读取受密码保护的word文档.以下代码适用于不受密码保护的文档,但是与受密码保护的文件一起使用时会出错.
I am trying to read a password protected word document on Python using zipfile.The following code works with a non-password protected document, but gives an error when used with a password protected file.
try:
from xml.etree.cElementTree import XML
except ImportError:
from xml.etree.ElementTree import XML
import zipfile
psw = "1234"
WORD_NAMESPACE = '{http://schemas.openxmlformats.org/wordprocessingml/2006/main}'
PARA = WORD_NAMESPACE + 'p'
TEXT = WORD_NAMESPACE + 't'
def get_docx_text(path):
document = zipfile.ZipFile(path, "r")
document.setpassword(psw)
document.extractall()
xml_content = document.read('word/document.xml')
document.close()
tree = XML(xml_content)
paragraphs = []
for paragraph in tree.getiterator(PARA):
texts = [node.text
for node in paragraph.getiterator(TEXT)
if node.text]
if texts:
paragraphs.append(''.join(texts))
return '\n\n'.join(paragraphs)
使用受密码保护的文件运行get_docx_text()时,出现以下错误:
When running get_docx_text() with a password protected file, I received the following error:
回溯(最近通话最近一次):
Traceback (most recent call last):
File "<ipython-input-15-d2783899bfe5>", line 1, in <module>
runfile('/Users/username/Workspace/Python/docx2txt.py', wdir='/Users/username/Workspace/Python')
File "/Applications/Spyder-Py2.app/Contents/Resources/lib/python2.7/spyderlib/widgets/externalshell/sitecustomize.py", line 680, in runfile
execfile(filename, namespace)
File "/Applications/Spyder-Py2.app/Contents/Resources/lib/python2.7/spyderlib/widgets/externalshell/sitecustomize.py", line 78, in execfile
builtins.execfile(filename, *where)
File "/Users/username/Workspace/Python/docx2txt.py", line 41, in <module>
x = get_docx_text("/Users/username/Desktop/file.docx")
File "/Users/username/Workspace/Python/docx2txt.py", line 23, in get_docx_text
document = zipfile.ZipFile(path, "r")
File "zipfile.pyc", line 770, in __init__
File "zipfile.pyc", line 811, in _RealGetContents
BadZipfile: File is not a zip file
有人对这个代码起作用有任何建议吗?
Does anyone have any advice to get this code to work?
感谢您分享您的知识和专业知识.
Thank you for sharing your knowledge and expertise.
推荐答案
我认为这不是加密问题,原因有两个:
I don't think this is an encryption problem, for two reasons:
-
在创建
ZipFile
对象时不尝试解密.诸如ZipFile.extractall
,extract
和open
和read
使用包含密码的可选pwd
参数,但对象构造函数/初始值设定项没有.
Decryption is not attempted when the
ZipFile
object is created. Methods likeZipFile.extractall
,extract
, andopen
, andread
take an optionalpwd
parameter containing the password, but the object constructor / initializer does not.
您的堆栈跟踪表明在创建ZipFile
对象时,正在调用setpassword
之前的 中,正在引发BadZipFile
:
Your stack trace indicates that the BadZipFile
is being raised when you create the ZipFile
object, before you call setpassword
:
document = zipfile.ZipFile(path, "r")
我会仔细检查正在测试的两个文件之间的其他差异:所有权,权限,安全性上下文(如果您的操作系统上有),...甚至文件名差异也可能导致框架看不到您正在处理的文件.
I'd look carefully for other differences between the two files you're testing: ownership, permissions, security context (if you have that on your OS), ... even filename differences can cause a framework to "not see" the file you're working on.
也---很明显的一个---尝试使用与zip兼容的命令打开加密的zip文件.看看它是否真的是 压缩文件.
Also --- the obvious one --- try opening the encrypted zip file with your zip-compatible command of choice. See if it really is a zip file.
我通过在Python 3.1中打开一个加密的zip文件进行了测试,同时忘记了"提供密码.我可以创建ZipFile
对象(下面的变量zfile
)而没有任何错误,但是遇到RuntimeError
--- not 不是BadZipFile
异常---当我尝试读取时没有提供密码的文件:
I tested this by opening an encrypted zip file in Python 3.1, while "forgetting" to provide a password. I could create the ZipFile
object (the variable zfile
below) without any error, but got a RuntimeError
--- not a BadZipFile
exception --- when I tried to read a file without providing a password:
Traceback (most recent call last):
File "./zf.py", line 35, in <module>
main()
File "./zf.py", line 29, in main
print_checksums(zipfile_name)
File "./zf.py", line 22, in print_checksums
for checksum in checksum_contents(zipfile_name):
File "./zf.py", line 13, in checksum_contents
inner_file = zfile.open(inner_filename, "r")
File "/usr/lib64/python3.1/zipfile.py", line 903, in open
"password required for extraction" % name)
RuntimeError: File apache.log is encrypted, password required for extraction
我还能够引发BadZipfile
异常,一次尝试打开一个空文件,一次尝试打开一些随机日志文件文本,然后将其重命名为".zip"扩展名.这两个测试文件产生了相同的堆栈跟踪,一直到行号.
I was also able to raise a BadZipfile
exception, once by trying to open an empty file and once by trying to open some random logfile text that I'd renamed to a ".zip" extension. The two test files produced identical stack traces, down to the line numbers.
Traceback (most recent call last):
File "./zf.py", line 35, in <module>
main()
File "./zf.py", line 29, in main
print_checksums(zipfile_name)
File "./zf.py", line 22, in print_checksums
for checksum in checksum_contents(zipfile_name):
File "./zf.py", line 10, in checksum_contents
zfile = zipfile.ZipFile(zipfile_name, "r")
File "/usr/lib64/python3.1/zipfile.py", line 706, in __init__
self._GetContents()
File "/usr/lib64/python3.1/zipfile.py", line 726, in _GetContents
self._RealGetContents()
File "/usr/lib64/python3.1/zipfile.py", line 738, in _RealGetContents
raise BadZipfile("File is not a zip file")
zipfile.BadZipfile: File is not a zip file
虽然此堆栈跟踪与您完全不相同-我的调用是_GetContents
,而3.2之前的小f"拼写是BadZipfile
- -但是它们之间的距离足够近,我认为这是您要解决的问题.
While this stack trace isn't exactly the same as yours --- mine has a call to _GetContents
, and the pre-3.2 "small f" spelling of BadZipfile
--- but they're close enough that I think this is the kind of problem you're dealing with.
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