本文介绍了在python中列出嵌套字典的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个列表如下
['item1', 'item2', 'item3', 'item4']
我想从上面的列表中构建一个字典如下
I want to construct a dictionary from the above list as follows
{
"item1": {
"item2": {
"item3": "item4"
}
}
}
列表中的项目数量是动态的。字典将是一个嵌套字典,直到它到达列表的最后一个元素。
python有没有办法这样做?
The number of items in the list is dynamic. The dictionary will be a nested dictionary till it reaches the last element of the list.Is there any way in python to do this?
推荐答案
简单单行:
a = ['item1', 'item2', 'item3','item4']
print reduce(lambda x, y: {y: x}, reversed(a))
为了更好地理解上述代码可以扩展为:
For better understanding the above code can be expanded to:
def nest_me(x, y):
"""
Take two arguments and return a one element dict with first
argument as a value and second as a key
"""
return {y: x}
a = ['item1', 'item2', 'item3','item4']
rev_a = reversed(a) # ['item4', 'item3', 'item2','item1']
print reduce(
nest_me, # Function applied until the list is reduced to one element list
rev_a # Iterable to be reduced
)
# {'item1': {'item2': {'item3': 'item4'}}}
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