PROLOG 打印以 7 结尾且其数字之和大于 100 的数字

问题描述

我需要创建一个接收数字列表的谓词，并仅打印以 7 结尾且其数字之和大于 100 的数字

I need to make a predicate that receives a numeric list and print only the numbers that end in 7 and that the sum of its digits is greater than 100

我为分离做了谓词，但我需要帮助将两个谓词合并，我的意思是这两个谓词进入一个唯一的谓词，这是我到目前为止所做的:

I made the predicates for separated but I need help making a union of the two predicates, I mean that the two predicates go into one only predicate, this is what I did so far:

%sum of digits greater than 100
 multi(X):-
0 is X mod 100
sum([],0).
sum([P|Q],Z).
multi(P), sum(Q,Z1), Z is P + Z1.
sum([P|Q],Z).
not multi(P), sum(Q,Z).

%print the numbers that end in 7
end(Y):-
7 is Y mod 10.
listend([],0).
listend([P|Q]):-
end(P),write(P), nl, listend(Q).
listend([P|Q]):-
not(end(P)), listend(Q).

推荐答案

这对我有用:

?- filter([147, 24, 57, 17, 3667], X), write(X), nl, fail.

sumdigits(0, 0).
sumdigits(X, Z) :-
    X > 0,
    Z1 is X mod 10,
    X2 is X // 10,
    sumdigits(X2, Z2),
    Z is Z1 + Z2.

filter([], []).
filter([H|X], [H|Y]) :-
    sumdigits(H, D),
    D > 10,
    7 is H mod 10, !,
    filter(X, Y).
filter([_|X], Y) :- filter(X, Y).

我明白了:

[147, 57, 3667]
No.

我假设你的意思是数字的总和大于 10，而不是 100.

I assumed you meant that the sum of the digits was greater than 10, rather than 100.

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