本文介绍了无法将类型'int'隐式转换为'int []'的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 29岁程序员,3月因学历无情被辞! 我正在尝试制作一个策划游戏,我让用户猜测4-10而不是颜色之间的数字序列但由于某种原因我的GetRandomNumberCount,CountHits得到错误不能隐式地将类型转换为int [] 任何指导都将不胜感激 // 此方法将随机数与用户猜测的随机数进行比较 public static int CountHits( int userGuess, int [] randomNumbers) { int correctGuess = 0 ; if (userGuess == randomNumbers) { Console.WriteLine( 点击); Console.ReadLine(); correctGuess ++; } else { Console.WriteLine( 小姐); Console.ReadLine(); } return correctGuess; } // 此方法获取在游戏中使用的随机数的数量。 public static int GetRandomNumberCount( int 难度) { int [] randomNumber = 0 ; if (难度== 1 ) { randomNumber = GenerateRandomNumber( 0 , 4 ); } 其他 如果(难度== 2 ) { randomNumber = GenerateRandomNumber( 1 , 6 ); } 其他 如果(难度== 3 ) { randomNumber = GenerateRandomNumber( 1 , 11 ); } return randomNumber; } // 此方法生成数字数组的随机数。 public static int [] GenerateRandomNumber( int min, int max) { // 这声明了一个包含5个元素的整数数组 // 并将所有这些值初始化为默认值 // 为零 int [] test2 = new int [ 5 ]; 随机randNum = 新 Random(); for ( int i = 0 ; i < test2.Length; i ++) { test2 [i] = randNum.Next(min,max); } return test2; } 解决方案 错误是否来自此行 int [] randomNumber = 0 ; 应该 randomNumber 是单个变量而不是数组吗? int [] randomNumber = new int [ ] {}; I am trying to make a mastermind game where I having the user guess a number sequence between 4-10 instead of colours but for some reason my GetRandomNumberCount, CountHits get the error Cannot implicitly convert type to int[]Any guidance would be appreciated// This method compares the random numbers to the ones the user has guessed public static int CountHits(int userGuess, int[] randomNumbers) { int correctGuess = 0; if(userGuess == randomNumbers) { Console.WriteLine("Hit"); Console.ReadLine(); correctGuess++; } else { Console.WriteLine("Miss"); Console.ReadLine(); } return correctGuess; }// This method gets the quantity of random numbers to use in the game. public static int GetRandomNumberCount(int difficulty) { int[] randomNumber = 0; if(difficulty == 1) { randomNumber= GenerateRandomNumber(0, 4); } else if(difficulty == 2) { randomNumber = GenerateRandomNumber(1, 6); } else if (difficulty == 3) { randomNumber = GenerateRandomNumber(1, 11); } return randomNumber; } // This method generates the random numbers for the array of numbers. public static int[] GenerateRandomNumber(int min, int max) { // this declares an integer array with 5 elements // and initializes all of them to their default value // which is zero int[] test2 = new int[5]; Random randNum = new Random(); for (int i = 0; i < test2.Length; i++) { test2[i] = randNum.Next(min, max); } return test2; } 解决方案 Is the error coming perhaps from this rowint[] randomNumber = 0;Should randomNumber be a single variable instead of an array ?int[] randomNumber = new int[] { }; 这篇关于无法将类型'int'隐式转换为'int []'的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云!