"MOST-OF"指的是"MOST-OF".在python中

问题描述

我有一个元素列表:

x = [1,3,5,7,9]
y = [2,4,6,8,0]

现在，我想执行一个操作，该操作为我提供了第三列表z中的元素存在"的列表:

Now I want to perform an operation which gives me the list in which "MOST OF" the elements in a third list z exist:

z = [2,3,5,7] #primes

我要这样做，以便返回z中具有"MOST OF"项的列表，而不是z中具有任何元素的列表.

I want to do it such that the list with "MOST OF" the items in z is returned,not the list with any element in z..

如果无法使用列表，则可以使用元组或集合了...

If it is not possible with lists, I am ready to work with tuples or sets as-well...

样本:

mostOf(z) -> x

因为x包含z中的大多数值

since x contains most of the values in z

推荐答案

使用集合，您可以查看相交的大小...

working with sets, you can look at the size of the intersection ...

 zset = set(z)
 if len(zset.intersection(x)) > len(zset.intersection(y)):
     ...

如果您有可迭代的列表要检查:

If you have an iterable of lists to check:

iterable = (x,y)

您可以从获得具有最大交点的迭代:

You can get the iterable with the biggest intersection from:

def cmp_key(lst):
    itersect_size = len(zset.intersection(lst))
    return intersect_size,-len(lst)

list_with_biggest_intersection = max(iterable,key = cmp_key)

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