#Lab 7-3 The Dice Game
#add libraries needed
import random
#the main function
def main():
print
#initiliaze variables
endProgram = 'no'
playerOne = 'NO NAME'
playerTwo = 'NO NAME'
#call to inputNames
playerOne, playerTwo = inputNames(playerOne, playerTwo)
#while loop to run program again
while endProgram == 'no':
winnersName = 'NO NAME'
p1number = 0
p2number = 0
#initiliaze variables
#call to rollDice
winnerName = rollDice(playerOne, playerTwo, winnerName)
#call to displayInfo
winnerName = displayInfo (winnerName)
endProgram = input('Do you want to end program?(Enter yes or no): ')
#this function gets players names
def inputNames():
inputNames = string('Enter your names: ')
return playerOne, playerTwo
#this function will get the random values
def rollDice():
p1number = random.randint(1,6)
p2number = random.randint(1,6)
if p1number >= p2number:
winnerName = playerOne
if p1number == p2numer:
winnerName = 'TIE'
elif winnerName == playerTwo:
return winnerName
#this function displays the winner
def displayInfo():
print ('The winner is: ', winnerName)
#calls main
main()
初学者程序员在这里并尝试完成作业。第19行返回错误:TypeError:inputNames()不接受任何参数(给定2个)。第19行:playerOne,playerTwo = inputNames(playerOne,playerTwo)。这行是由我的教授提供的,我无法弄清楚如何使它起作用。任何帮助将不胜感激!
最佳答案
函数inputNames被定义为不带参数的函数,但是您要在方法列表中向其传递两个变量:
这是您的定义方式:
def inputNames():
inputNames = string('Enter your names: ')
return playerOne, playerTwo
这是你的称呼:
playerOne, playerTwo = inputNames(playerOne, playerTwo)
您真正想要的是此函数返回播放器一和播放器二的名称。所以上面的行应该是:
playerOne, playerTwo = inputNames()
并且该函数将必须在本地收集两个名称并返回它们,也许是这样的:
def inputNames():
p1 = str(raw_input("Enter the name for player one: "))
p2 = str(raw_input("Enter the name for player two: "))
return p1, p2
关于python - TypeError:inputNames()不接受任何参数(给定2个),我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/10304619/