我想使用RaspberryPI3从IP摄像机获取图像,我编写了这段代码,但是当我单击“按钮”时,系统崩溃了,App.g.i.cs中抛出了异常,我该如何修复该代码?
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.IO;
using System.Linq;
using System.Net;
using System.Runtime.InteropServices.WindowsRuntime;
using Windows.Foundation;
using Windows.Foundation.Collections;
using Windows.Storage.Streams;
using Windows.UI.Xaml;
using Windows.UI.Xaml.Controls;
using Windows.UI.Xaml.Controls.Primitives;
using Windows.UI.Xaml.Data;
using Windows.UI.Xaml.Input;
using Windows.UI.Xaml.Media;
using Windows.UI.Xaml.Media.Imaging;
using Windows.UI.Xaml.Navigation;
using Windows.Web.Http;
namespace App6
{
public sealed partial class MainPage : Page
{
public MainPage()
{
this.InitializeComponent();
}
private async void Sample()
{
Windows.Storage.Streams.IRandomAccessStream random = await Windows.Storage.Streams.RandomAccessStreamReference.CreateFromUri(new Uri("http://192.168.1.253/SnapShotJPEG?Resolution=320x240&Quality=Motion")).OpenReadAsync();
Windows.Graphics.Imaging.BitmapDecoder decoder = await Windows.Graphics.Imaging.BitmapDecoder.CreateAsync(random);
Windows.Graphics.Imaging.PixelDataProvider pixelData = await decoder.GetPixelDataAsync();
byte[] bytes = pixelData.DetachPixelData();
BitmapImage image = new BitmapImage();
using (InMemoryRandomAccessStream stream = new InMemoryRandomAccessStream())
{
await stream.WriteAsync(bytes.AsBuffer());
stream.Seek(0);
await image.SetSourceAsync(stream);
}
IpCamera_1.Source = image; //IpCamera_1 is Image.
}
private void Hello_Click(object sender, RoutedEventArgs e)
{
Sample();
}
}
}
是否存在另一种解决方案,将视频从IP摄像机流传输到Raspberry-Pi?我正在使用Windows-10-iot-core。
最佳答案
因为您正在连接到本地网络,所以应该向Package.appxmanifest
添加一些必需的功能。在解决方案资源管理器中右键单击该文件,选择View code
,然后在<Capabilities>
元素中添加以下内容:
<Capabilities>
<Capability Name="internetClient" />
<Capability Name="internetClientServer" />
<Capability Name="privateNetworkClientServer" />
</Capabilities>
关于c# - 从IP摄像机,UWP获取位图图像,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/48915748/