我需要能够检测数据库和/或表是否存在于单个查询中,以采取相应的措施。我有这个丑陋的查询工作:

SELECT * FROM

(SELECT COUNT(*) AS `database`
FROM INFORMATION_SCHEMA.SCHEMATA
WHERE SCHEMATA.SCHEMA_NAME="database_name") AS foo,

(SELECT COUNT(*) AS `table`
FROM INFORMATION_SCHEMA.TABLES
WHERE table_schema = "database_name"
AND table_name = "table_name") AS bar


该查询返回:

database    table
1           0


但是...也许那里有更好的方法。

最佳答案

使用左联接:

SELECT schemata.schema_name AS `database_name`, tables.table_name
FROM INFORMATION_SCHEMA.SCHEMATA schemata
LEFT JOIN INFORMATION_SCHEMA.TABLES tables
  ON schemata.schema_name = tables.table_schema
  AND tables.table_name = "table_name"
WHERE SCHEMATA.SCHEMA_NAME="database_name"

关于mysql - 检测数据库和表是否存在于同一查询中,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/16694616/

10-15 08:22