python - Python中的简单射箭游戏

我刚开始用蟒蛇，我想做一个小小的射箭游戏。然而，它在这一点上产生了一个错误：d=math.sqrt（x*x+y*y）（即新点和冰斗的原始中心之间的距离）有什么关于这不起作用的想法吗？

def archery():

    win = GraphWin("Archery Game", 500,500)
    win.setCoords(-50, -50, 50, 50)

    circle1 = Circle(Point(0,0), 40)
    circle1.setFill("white")
    circle1.draw(win)

    circle2 = Circle(Point(0,0), 35)
    circle2.setFill("black")
    circle2.draw(win)

    circle3 = Circle(Point(0,0), 30)
    circle3.setFill("blue")
    circle3.draw(win)

    circle4 = Circle(Point(0,0), 25)
    circle4.setFill("red")
    circle4.draw(win)

    circle5 = Circle(Point(0,0), 20)
    circle5.setFill("yellow")
    circle5.draw(win)

    score = 0

    for i in range(5):
        p = win.getMouse()
        p.draw(win)
        x = p.getX
        y = p.getY

        d = math.sqrt(x*x + y*y)

        if 40 >= d > 35:
            score = score + 1

        elif 35 >= d > 30:
            score = score + 3

        elif 30 >= d > 25:
            score = score + 5

        elif 25 >= d > 20:
            score = score + 7

        elif 20 >= d >= 0:
            score = score + 9
        else:
            score = score + 0

        print("Your current score is:", score)

    win.getMouse()
    win.close()

最佳答案

    x = p.getX
    y = p.getY

将返回函数getX和getY，而不是执行它。正如Mike Steder所说，trygetX()，它应该返回一个值。

关于python - Python中的简单射箭游戏，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/5108434/