我想要这样的输出
5 4 3 2 1 2 3 4 5
4 3 2 1 2 3 4
3 2 1 2 3
2 1 2
1
如何在左侧留出空间?
public class Exercise4_17 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the number of lines: ");
int num = input.nextInt();
Exercise4_17 exe = new Exercise4_17();
exe.displayPyramid(num);
}
private void displayPyramid(int num) {
for (int i = num; i >= 1; i--) {
for (int space = 1; space <= num - i; ++space) {
System.out.print(" ");
}
for (int k = num; k >= 1; k--) {
System.out.print(k + " ");
}
for (int j = 2; j <= num; j++) {
System.out.print(j + " ");
}
System.out.println();
num--;
}
}
}
我的输出
Enter the number of lines: 5
5 4 3 2 1 2 3 4 5
4 3 2 1 2 3 4
3 2 1 2 3
2 1 2
1
最佳答案
您的代码非常接近。首先,作为样式,我将在第二个循环中使用相同的变量名(j
令人讨厌,只需使用k
)。其次,也是真正的问题,您正在修改循环中的num
。在循环之前保存初始值,并将其用于空间计算。喜欢,
final int initial = num; // <-- add this
for (int i = num; i >= 1; i--) {
for (int space = 1; space <= initial - i; ++space) { // <-- use initial instead of num
System.out.print(" ");
}
for (int k = num; k >= 1; k--) {
System.out.print(k + " ");
}
for (int k = 2; k <= num; k++) { // <-- j should still work of course...
System.out.print(k + " ");
}
System.out.println();
num--;
}
关于java - 显示倒金字塔,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47967450/