我已经创建了静态数据库,这个数据库为图像添加了基64字符串这个图像很大我运行了我的应用程序,同时为数据库获取字符串获取错误如何解决它。
我是Android编程新手…
数据库

public List<People> getAllPeople() {

    List<People> peoples = new ArrayList<>();

    try {
        SQLiteDatabase db = SQLiteDatabase.openDatabase(DB_PATH + DB_NAME, null, SQLiteDatabase.OPEN_READWRITE);
        Cursor cursor = db.rawQuery("select * from " + TABLE_PEOPLE, null);
        while (cursor.moveToNext()) {
            if (cursor != null) {
                String peopleImage = cursor.getString(cursor.getColumnIndex(PEOPLE_IMAGE));\\ This line getting error
                String categoryId = cursor.getString(cursor.getColumnIndex(CATEGORY_ID));
                String peopleName = cursor.getString(cursor.getColumnIndex(PEOPLE_NAME));
                String peopleId = cursor.getString(cursor.getColumnIndex(ID));
                int status = cursor.getInt(cursor.getColumnIndex(STATUS));
                String month = cursor.getString(cursor.getColumnIndex(PEOPLE_MONTH));
                String date = cursor.getString(cursor.getColumnIndex(PEOPLE_DATE));
                String year = cursor.getString(cursor.getColumnIndex(PEOPLE_YEAR));
                String peopleDetail = cursor.getString(cursor.getColumnIndex(PEOPLE_DETAIL));


                People people = new People();
                people.setId(peopleId);
                people.setPeopleName(peopleName);
                people.setPeopleImage(peopleImage);
                people.setStatus(status);
                people.setMonth(month);
                people.setDate(date);
                people.setYear(year);
                people.setPeopleDetail(peopleDetail);
                people.setCategoryId(categoryId);

                peoples.add(people);
            }
        }
    } catch (Exception e) {
        Log.d("DB", e.getMessage());
    }
    return peoples;
}

适配器
byte[] decodedString = Base64.decode(people.getPeopleImage(), Base64.DEFAULT);
    BitmapFactory.Options options = new BitmapFactory.Options();
    options.inJustDecodeBounds = true;
    BitmapFactory.decodeByteArray(decodedString, 0, decodedString.length, options);
    options.inSampleSize = calculateInSampleSize(options, 100, 100);
    options.inJustDecodeBounds = false;
    Bitmap bmp1 = BitmapFactory.decodeByteArray(decodedString, 0, decodedString.length, options);
    if (bmp1 != null) {
        holder.ivPeopleImage.setImageBitmap(bmp1);
    }

最佳答案

就我个人而言,我不认为在数据库中存储图像是个好主意。将它们保存在base64中会使您的解决方案更慢,您需要在每次操作它们时进行编码和解码。我的建议是,将图像文件保存在存储媒体上,并将uri保存在数据库中,这样做更快、更易于管理。
如果你真的需要用你的方式去做,不管是什么原因…尝试在android:largeHeap="true"中设置AndroidManifest.xml
更新:

  private static final String FOLDER="/MyApp/";
  private static String saveBitmapToSd(Bitmap bmp, String fileName){
        String pngName=Environment.getExternalStorageDirectory().toString()+FOLDER+fileName+".png";
        FileOutputStream fos= null;
        boolean success=false;
        try {
            fos = new FileOutputStream(new File(pngName));
            bmp.compress(Bitmap.CompressFormat.PNG,100,fos);
            success=true;
        } catch (FileNotFoundException e) {
            Log.e(TAG, "saveBitmapToSd: ", e);
        }
        finally {
            if(fos!=null)
                try {
                    fos.close();
                } catch (IOException e) {
                    Log.e(TAG, "saveBitmapToSd: ",e );
                }
        }
        if(success)
            return pngName;
        else
            return null;
    }

这是将位图保存到SD卡并返回路径字符串的方法。
我刚刚写了一个非常简单的演示程序,你可以在这里查看。
Demo App

关于java - android中的android.database.CursorWindow.getString处的java.lang.OutOfMemoryError,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/40648190/

10-13 09:39