php - 每组2行之间选择

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--
-- Database: `items`
--

-- --------------------------------------------------------

--
-- Table structure for table `tests`
--

CREATE TABLE `tests` (
  `ID` int(4) NOT NULL,
  `SID` int(4) NOT NULL,
  `VID` int(4) NOT NULL,
  `Text` varchar(20) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

--
-- Indexes for dumped tables
--

--
-- Indexes for table `tests`
--
ALTER TABLE `tests`
  ADD PRIMARY KEY (`ID`);

--
-- AUTO_INCREMENT for dumped tables
--

--
-- AUTO_INCREMENT for table `tests`
--
ALTER TABLE `tests`
  MODIFY `ID` int(4) NOT NULL AUTO_INCREMENT;
COMMIT;

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我知道了，但我不知道如何将它们搭配在一起：

在2行之间选择：

SELECT
    MAX(`VID`)-3 AS max1,
    MAX(`VID`)-2 AS max2
FROM `tests`
GROUP BY `SID`

返回行的值：

SELECT *
FROM `tests`
WHERE `VID`>='max1' AND `VID`<='max2'
ORDER BY `SID` ASC, `VID` ASC

结果应该是这样的：

**Group:1**

test - 3

test - 4

**Group:2**

test - 283

test - 284

**Group:3**

test - 197

test - 198

**Group:4**

test - 173

test - 174

**Group:5**

test - 117

test - 118

**Group:6**

test - 162

test - 163

**Group:7**

test - 203

test - 204

**Group:8**

test - 72

test - 73

**Group:9**

test - 126

test - 127

**Group:10**

test - 106

test - 107

最佳答案

您可以将表与包裹在子查询中的汇总表结合起来：

    SELECT t.*
      FROM tests t
      JOIN (
                SELECT SID
                     , MAX(VID)-3 AS max1
                     , MAX(VID)-2 AS max2
                  FROM tests
              GROUP BY SID
           ) tagg
        ON tagg.SID = t.SID
     WHERE t.VID >= tagg.max1
       AND t.VID <= tagg.max2
  ORDER BY t.SID
         , t.VID
         ;

关于php - 每组2行之间选择，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/51670123/