ios - Xcode Swift-无法使用 'pathForResource'类型的参数列表调用 '(String!)'

由于出现以下错误，请帮助我修复代码:



错误在以下代码行上:

let urlpathString:String? = NSBundle.mainBundle().pathForResource(url)

我的完整代码:

import UIKit
import AVKit
import AVFoundation
import MediaPlayer

class ViewController: UIViewController {

    let avPlayerViewControler = AVPlayerViewController()
    var avPlayer:AVPlayer?
    var videoNumber:Int!
    var url:String!

    override func viewDidLoad() {
        super.viewDidLoad()
    }

    func playVideo() {
        switch videoNumber {
            case 1 : url="20"
            case 2 : url="10"
            default : break

            let urlpathString:String? = NSBundle.mainBundle().pathForResource(url)

            if let urlPath = urlpathString {
                let movieUrl = NSURL(fileURLWithPath: urlPath)
                self.avPlayer = AVPlayer(URL: movieUrl)
                self.avPlayerViewControler.player = self.avPlayer

            }
        }
    }

    @IBAction func Button(sender: UIButton){
        videoNumber=1
        playVideo()
    }

    @IBAction func Button2(sender: UIButton) {
        videoNumber=2
        playVideo()
    }
}

最佳答案

没有pathForResource的简单NSBundle方法，至少有第二个参数，例如pathForResource:ofType:
由于仍然需要NSURL，因此请使用URL发布的API，将整个if let表达式替换为

func playVideo() {
  switch videoNumber {
    case 1 : url="20"
    case 2 : url="10"
    default : break
  }

  if let movieUrl = NSBundle.mainBundle().URLForResource(url, withExtension: "mp4") {
     self.avPlayer = AVPlayer(URL: movieUrl)
     self.avPlayerViewControler.player = self.avPlayer
  }
}

您必须将mp4更改为预期的扩展名。

关于ios - Xcode Swift-无法使用 'pathForResource'类型的参数列表调用 '(String!)'，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/37712603/