语境
我有一个名为Entity
的基类,并且User
和Group
都从该对象派生;例如,如果实例化ID
为12的用户,则下次尝试这样做时,它将返回相同的对象。我将它们存储在原型items
变量中。为了使这些item
变量分开,我必须分别声明User和Group函数,尽管它们包含相同的代码。
码
Application.prototype.Entity = function() {
};
Application.prototype.Entity.prototype.print = function() {
var container = $("<div class='user-tag'></div>");
container.append("<a class='friend_list ellipsis_overflow' style='background-image:url(\"" + this.entity.pic.icon + "\");'"
+ "href ='user?id=" + this.entity.id + "'>" + this.entity.name + "</a>");
return container;
};
//HOW TO GET RID OF THIS "REPETITION"
Application.prototype.User = function(entity) {
this.entity = entity;
this.entity.pic = this.entity.pic || Application.prototype.default.pic;
if (this.items[this.entity.id]) {
return this.items[this.entity.id];
} else {
this.items[this.entity.id] = this;
}
};
Application.prototype.Group = function(entity) {
this.entity = entity;
this.entity.pic = this.entity.pic || Application.prototype.default.pic;
if (this.items[this.entity.id]) {
return this.items[this.entity.id];
} else {
this.items[this.entity.id] = this;
}
};
// END REPEAT
Application.prototype.Group.prototype = new Application.prototype.Entity();
Application.prototype.User.prototype = new Application.prototype.Entity();
//Application.prototype.User.prototype.constructor = Application.prototype.Entity;
//Application.prototype.Group.prototype.constructor = Application.prototype.Entity; - these don't seem to work
//THESE items VARIABLES HAVE TO REMAIN SEPARATE
Application.prototype.Group.prototype.items = {};
Application.prototype.User.prototype.items = {};
题
我特别希望摆脱上面提到的重复代码,但是如果您看到其他不必要的代码,请发表评论。谢谢!
最佳答案
像这样吗
function userAndGroupConstructor(entity) {
this.entity = entity;
this.entity.pic = this.entity.pic || Application.prototype.default.pic;
if (this.items[this.entity.id]) {
return this.items[this.entity.id];
} else {
this.items[this.entity.id] = this;
}
}
Application.prototype.User = function() {
return userAndGroupConstructor.apply(this, arguments)
}
Application.prototype.Group = function() {
return userAndGroupConstructor.apply(this, arguments)
}
您将获得具有不同原型的独特构造函数,但要避免重复。
关于javascript - JavaScript类扩展,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/23723133/