我有一个名为“eposodeinfodata”的属性类
class EpisodeInfoData {
var episodeId = ""
var episodeName = ""
}
我已经将这些类的对象存储到字典中,字典的第一个元素是“String”,另一个元素是“eposodeinfodata”类对象的数组
var episodes = Dictionary<String, [EpisodeInfoData]>()
let infoObj1 = EpisodeInfoData()
infoObj1.episodeId = "1"
infoObj1.episodeName = "one"
let infoObj2 = EpisodeInfoData()
infoObj2.episodeId = "2"
infoObj2.episodeName = "two"
let infoObj3 = EpisodeInfoData()
infoObj3.episodeId = "3"
infoObj3.episodeName = "three"
let infoObj4 = EpisodeInfoData()
infoObj4.episodeId = "4"
infoObj4.episodeName = "four"
let infoObj5 = EpisodeInfoData()
infoObj5.episodeId = "5"
infoObj5.episodeName = "five"
let infoObj6 = EpisodeInfoData()
infoObj6.episodeId = "6"
infoObj6.episodeName = "six"
let infoObj7 = EpisodeInfoData()
infoObj7.episodeId = "7"
infoObj7.episodeName = "seven"
let infoObj8 = EpisodeInfoData()
infoObj8.episodeId = "8"
infoObj8.episodeName = "eight"
episodes["season1"] = [infoObj1,infoObj2,infoObj3,infoObj4]
episodes["season2"] = [infoObj5,infoObj6,infoObj7,infoObj8]
我想在“情节”字典里找到季节的名字,它的书名是“八”。我试着用过滤镜了它不工作了。
有人能给我建议什么吗?不用过滤器就用过滤器找到结果。
提前谢谢你
最佳答案
不得不加上另一个答案,感谢那些在没有真正帮助的情况下投了反对票的人。
试试这个
if let episode = (episodes.filter { $0.1.contains { $0.episodeName == "eight" } }).first {
print(episode.0) // season2
}
关于ios - 在对象数组字典中应用过滤器,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/39826104/