c++ - 检索静态char *数组失败

我有以下代码片段，目的是获取某些项目列表并打印。它可以正常编译，但是在运行时，输出不符合预期。我在结果意外的地方添加了评论。请让我知道我在做什么错。

#include <iostream>

using namespace std;

class cSample
{
private:
    static const char *list1[];
    static const char *list2[];

public:
    cSample();
    const char **GetList(int);
};

cSample::cSample()
{
}

const char *cSample::list1[] = {"Item1" , "Item2" , "Item3"};
const char *cSample::list2[] = {"Item4" ,"Item5" ,"Item6"};

const char **cSample::GetList(int i)
{
    switch(i)
    {
    case 1:
        return cSample::list1;
        break;
    case 2:
        return cSample::list2;
        break;
    default:
        break;
    }
}

int main(int argc , const char *argv[])
{
    cSample *oSample = new cSample();

    const char**list1Item = oSample->GetList(1);//Here getlist returns list1+list2 item which is wrong , I am not sure why...
    cout << "Items from List1 " << endl;
    while(*list1Item != NULL)
    {
        cout << *list1Item << endl;
        list1Item++;
    }

    const char **list2Item = oSample->GetList(2);//whereas list2 items are returned correctly using same method any idea why?
    cout << "Items from list2" << endl;
    while(*list2Item != NULL)
    {
        cout << *list2Item << endl;
        list2Item++;
    }
    return 0;
}

最佳答案

您需要添加一个NULL以终止您的列表

const char *cSample::list1[] = {"Item1" , "Item2" , "Item3", NULL};

关于c++ - 检索静态char *数组失败，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/26292967/