我试图通过单元格的“编辑”表视图行操作将数据从表视图单元传递到另一个视图控制器。

override func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {

    let edit = UITableViewRowAction(style: .normal, title: "Edit") { (action, indexPath) in

        let editViewController = self.storyboard?.instantiateViewController(withIdentifier: "EditViewController") as! EditViewController
        self.present(editViewController, animated: true, completion: nil)

        let cell = self.recipeList[indexPath.row] as? RecipeTableViewCell

        editViewController.nameTextField.text = cell?.recipeNameLabel.text
    }

    edit.backgroundColor = UIColor(red: 167.0/255.0, green: 204.0/255.0, blue: 181.0/255.0, alpha: 1.0)

    return [edit]
}


这是我的行行为函数的单元格...

override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

    let cell = tableView.dequeueReusableCell(withIdentifier: "RecipeCell", for: indexPath) as! RecipeTableViewCell

    let recipe = recipeList[indexPath.row]

    cell.recipeNameLabel!.text = recipe.name
    cell.ratingControl.rating = recipe.rating
    }
    return cell
}

最佳答案

而不是传递目标VC中的每个值,而是尝试仅传递recipe对象。然后从该对象获取值并填写控件。

1)在recipe中创建EditViewController对象

 var editRecipe : Recipe! // Your Model class


2)赋值

let editViewController = self.storyboard?.instantiateViewController(withIdentifier: "EditViewController") as! EditViewController
editViewController. editRecipe = recipeList[indexPath.row]
self.present(editViewController, animated: true, completion: nil)


3)在ViewDidloadEditViewController

if editRecipe != nil {
    //Fill data in lbls
    //lbl_name.text = editRecipe.name
}

关于ios - 如何将标签中的数据从表 View 行操作发送到 View Controller ?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/54216565/

10-13 03:49