python - Pandas :使用DatetimeIndices列表从DataFrame中提取多行

我有一个熊猫数据框，其以下索引的频率为秒：

DatetimeIndex(['2015-12-28 05:20:05', '2015-12-28 05:20:06',
               '2015-12-28 05:20:07', '2015-12-28 05:20:08',
               ...
               '2015-12-28 21:19:55', '2015-12-28 21:19:56',
               '2015-12-28 21:19:57', '2015-12-28 21:19:58']

给定日期时间字符串列表，我想一次提取多行。我试过了：

df.loc[['2015-12-28 08:32:39', '2015-12-28 08:32:48']]

但是我收到以下错误：

KeyError: "None of [['2015-12-28 08:32:39', '2015-12-28 08:32:48']] are in the [index]"

最佳答案

您可以通过list或datetime将DatetimeIndex转换为to_datetime：

d = ['2015-12-28 05:20:05', '2015-12-28 21:19:58']
print (df.loc[pd.DatetimeIndex(d)])

要么：

print (df.loc[pd.to_datetime(d)])

样品：

idx = pd.DatetimeIndex(['2015-12-28 05:20:05', '2015-12-28 05:20:06',
               '2015-12-28 05:20:07', '2015-12-28 05:20:08',
               '2015-12-28 21:19:55', '2015-12-28 21:19:56',
               '2015-12-28 21:19:57', '2015-12-28 21:19:58'])
df = pd.DataFrame({'s': range(8)}, index=idx)
print (df)
                     s
2015-12-28 05:20:05  0
2015-12-28 05:20:06  1
2015-12-28 05:20:07  2
2015-12-28 05:20:08  3
2015-12-28 21:19:55  4
2015-12-28 21:19:56  5
2015-12-28 21:19:57  6
2015-12-28 21:19:58  7

d = ['2015-12-28 05:20:05', '2015-12-28 21:19:58']
print (df.loc[pd.to_datetime(d)])
                     s
2015-12-28 05:20:05  0
2015-12-28 21:19:58  7

print (df.loc[pd.to_datetime(d)])
                     s
2015-12-28 05:20:05  0
2015-12-28 21:19:58  7

关于python - Pandas :使用DatetimeIndices列表从DataFrame中提取多行，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/45213834/