javascript - 使用lodash创建父子关系

根据索引值组合父级和chid JSON数组，然后向其添加另一个发现的属性。

数据：比较字段：
parentJSON-索引
childJSON-parent_index

输出：
-父母
-及其孩子
-父母
-及其孩子

parentJSON:
[{ index:1, name: 'a'}, {index:2, name: 'b'}, {index:3, name: 'c'}, {index:4, name: 'd'}]

childJSON:
[
  { index:1, name: 'aa', parent_index:1},
  {index:2, name: 'ab', parent_index:1},
  {index:3, name: 'ba', parent_index: 2},
  {index:4, name: 'bb', parent_index: 2},
  {index:5, name: 'ca', parent_index: 3},
  {index:6, name: 'ad', parent_index: 1}
]

output:
[
  { index:1, name: 'a'},
  { index:1, name: 'aa', parent_index:1, found: true},
  { index:2, name: 'ab', parent_index:1, found: true},
  { index:6, name: 'ad', parent_index:1, found: true},
  { index:2, name: 'b'},
  { index:3, name: 'ba', parent_index:2, found: true},
  { index:4, name: 'bb', parent_index:2, found: true},
  { index:3, name: 'c'},
  { index:5, name: 'ca', parent_index:3, found: true},
  { index:4, name: 'd'},
]

Plunker Link

最佳答案

let parentJSON =
[{ index:1, name: 'a'}, {index:2, name: 'b'}, {index:3, name: 'c'}, {index:4, name: 'd'}]

let childJSON =
[
  { index:1, name: 'aa', parent_index:1},
  {index:2, name: 'ab', parent_index:1},
  {index:3, name: 'ba', parent_index: 2},
  {index:4, name: 'bb', parent_index: 2},
  {index:5, name: 'ca', parent_index: 3},
  {index:6, name: 'ad', parent_index: 1}
]

let answer = [];

parentJSON.forEach(parent => {
  answer.push(parent);

  childJSON.forEach(child => {
  	if(child.parent_index === parent.index){
    	child.found = true;

      answer.push(child);
    }
  })
});

console.log(answer)

在不知道您如何期望childJSON在parentJSON中不存在的情况下，上述解决方案假设childJSON的所有元素都有指向parent_index的parentJSON链接。

如果您更新了问题，请告诉我，除非这正是您想要的

关于javascript - 使用lodash创建父子关系，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/50519730/