python - 寻找排名最高的值

我有类别

Rank   Fruits:      Vegetable:    Years:
1      Apple        Lettuce       1900-1909
2      Pineapple    Carrot        1900-1909
3      Orange       Potato        1900-1909
4      Banana       Beans         1900-1909
 Rank   Fruits:      Vegetable:    Years:
 1      Banana       Carrot        1910-1919
 2      Orange       Potato        1910-1919
 3      Apple        Beans         1910-1919
 4      Pineapple    Lettuce       1910-1919

这是我上面给出的数据。我想知道何时香蕉水果最受欢迎（又名排名最接近1的香蕉）。我还需要找到胡萝卜最受欢迎的时间。

例如，我需要它来显示Carrot的结果是1910-1919，Banana的结果是1910-1919。

我已经搞了好几个小时了。我尝试将它们放入集合并使用键和值对其进行配置，但是我所做的一切都没有起作用。我真的很感谢您的帮助。谢谢！

def getHighRank(data):
    nameSet=()
    nameList=[]
    for names in data:
        nameList.append[1]
        nameList.append[2]

到目前为止，这就是我所拥有的。我尝试将水果和蔬菜放入一个清单中。我当时正在考虑将其转换为集合，但是对于现在该做什么我一无所知。

最佳答案

>>> d = {}
>>> with open('test.txt') as f:
        print f.read() # shows the file structure


Rank   Fruits:      Vegetable:    Years:
1      Apple        Lettuce       1900-1909
2      Pineapple    Carrot        1900-1909
3      Orange       Potato        1900-1909
4      Banana       Beans         1900-1909
Rank   Fruits:      Vegetable:    Years:
1      Banana       Carrot        1910-1919
2      Orange       Potato        1910-1919
3      Apple        Beans         1910-1919
4      Pineapple    Lettuce       1910-1919
>>> with open('test.txt') as f:
        for line in f:
            try:
                rank, fruit, vegetable, year = line.split()
                for k in (fruit, vegetable): # for both the fruit and veg
                    t = (rank, year) # tuple of rank and year
                    d[k] = min(d.get(k, t), t) # set it to the min (rank, year)
            except: # skip headers
                pass


>>> d['Apple'] # fast lookup
('1', '1900-1909')
>>> d['Apple'][1]
'1900-1909'
>>> d['Carrot'][1]
'1910-1919'
>>> d['Banana'][1]
'1910-1919'

关于python - 寻找排名最高的值，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/15983425/