我正在使用 matplotlib 烛台模块，该模块需要将时间作为 float 日期格式传递。我使用 date2num 来转换它，之前:
这是我的代码:
import csv
import sys
import math
import numpy as np
import datetime
from optparse import OptionParser
import matplotlib.pyplot as plt
import matplotlib.cbook as cbook
import matplotlib.mlab as mlab
import matplotlib.dates as mdates
from matplotlib.finance import candlestick
from matplotlib.dates import date2num
datafile = 'historical_data/AUD_Q10_1D_500.csv'
print 'loading', datafile
r = mlab.csv2rec(datafile, delimiter=';')
quotes = [date2num(r['date']),r['open'],r['close'],r['max'],r['min']]
candlestick(ax, quotes, width=0.6)
plt.show()
(这是 csv 文件:http://db.tt/MIOqFA0)
这就是文档所说的:
这是完整的错误日志:
Traceback (most recent call last):
File
"/usr/lib/python2.6/site-packages/matplotlib/backends/backend_qt4agg.py",
line 83, in paintEvent
FigureCanvasAgg.draw(self) File
"/usr/lib/python2.6/site-packages/matplotlib/backends/backend_agg.py",
line 394, in draw
self.figure.draw(self.renderer) File
"/usr/lib/python2.6/site-packages/matplotlib/artist.py",
line 55, in draw_wrapper draw(artist,
renderer, *args, **kwargs) File
"/usr/lib/python2.6/site-packages/matplotlib/figure.py",
line 798, in draw func(*args) File
"/usr/lib/python2.6/site-packages/matplotlib/artist.py",
line 55, in draw_wrapper draw(artist,
renderer, *args, **kwargs) File
"/usr/lib/python2.6/site-packages/matplotlib/axes.py", line 1946, in draw a.draw(renderer)
File
"/usr/lib/python2.6/site-packages/matplotlib/artist.py",
line 55, in draw_wrapper draw(artist,
renderer, *args, **kwargs) File
"/usr/lib/python2.6/site-packages/matplotlib/axis.py", line 971, in draw tick_tups = [ t for
t in self.iter_ticks()] File
"/usr/lib/python2.6/site-packages/matplotlib/axis.py", line 904, in iter_ticks majorLocs =
self.major.locator() File
"/usr/lib/python2.6/site-packages/matplotlib/dates.py",
line 743, in __call__ self.refresh()
File
"/usr/lib/python2.6/site-packages/matplotlib/dates.py",
line 752, in refresh dmin, dmax =
self.viewlim_to_dt() File
"/usr/lib/python2.6/site-packages/matplotlib/dates.py",
line 524, in viewlim_to_dt return
num2date(vmin, self.tz),
num2date(vmax, self.tz) File
"/usr/lib/python2.6/site-packages/matplotlib/dates.py",
line 289, in num2date if not
cbook.iterable(x): return
_from_ordinalf(x, tz) File "/usr/lib/python2.6/site-packages/matplotlib/dates.py",
line 203, in _from_ordinalf dt =
datetime.datetime.fromordinal(ix)
ValueError: ordinal must be >= 1
如果我快速运行:
for x in r['date']:
print str(x) + "is :" + str(date2num(x))
它输出类似:
2010-06-12is :733935.0
2010-07-12is :733965.0
2010-08-12is :733996.0
这对我来说听起来不错:)
最佳答案
更仔细地阅读文档字符串:)
发生的事情是它期望 quotes 的每一项都是(时间、开盘、收盘、高、低)的序列。
您传入 5 个长数组，它需要 5 个项目的长序列。
你只需要 zip 你的输入。
import matplotlib.pyplot as plt
import matplotlib.mlab as mlab
from matplotlib.finance import candlestick
from matplotlib.dates import date2num
datafile = 'Downloads/AUD_Q10_1D_500.csv'
r = mlab.csv2rec(datafile, delimiter=';')
quotes = zip(date2num(r['date']),r['open'],r['close'],r['max'],r['min'])
fig, ax = plt.subplots()
candlestick(ax, quotes, width=0.6)
plt.show()
关于python - date2num , ValueError : ordinal must be >= 1，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/6301400/