表格:lead_salesperson
------------------------
id | sp_id | phone
------------------------
0 | 1 | 12345678
1 | 1 | 87654321
表:productProperties
------------------------------------------------
product | sp_id | phone | activity_name
------------------------------------------------
0 | 1 | 12345678 | vm
1 | 1 | 12345678 | DNC
2 | 1 | 87654321 | SCB
3 | 1 | 77654321 | SCB
Select DISTINCT(l.phone) as phone
from lead_salesperson as l
join lead_activity as ls
on (ls.phone=l.phone) && (ls.year_make=l.year_make) && (ls.make=l.make)
where l.sp_id=$sp_id and ((ls.act_name!='DNC') OR (ls.act_name!='DNC_AUTO'))
因此输出应为
87654321,77654321
我正在尝试获取所有没有DNC或DNC_AUTO的电话号码... Leadactivity可以将多行连接到lead_salesperson中的一行。如果即使其中一行(电话)在activity_name中具有DNC或DNC _AUTO,那么我也不希望该电话成为结果集的一部分,请提出任何想法...如何解决此问题。
最佳答案
我认为您可以通过定义要排除的电话的子查询来解决此问题:
select distinct phone
from lead_activity as ls
where act_name in ('DNC', 'DNC_AUTO')
现在,您可以将此查询用作条件:
select distinct
l.phone as phone
from
lead_salesperson as l
where
phone not in (
select distinct phone
from lead_activity as ls
where act_name in ('DNC', 'DNC_AUTO'))
希望这对您有帮助
关于mysql - mysql之一是很多rquery,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13191131/