我在 R 中有一个数据集，我想在其中显示错误栏，但是它没有正确绘制(见图)。我还包括了我的数据集。
ant.d<-structure(list(group.name = structure(c(1L, 18L, 20L, 24L, 8L,
13L, 15L, 17L, 12L, 19L, 21L, 22L, 23L, 9L, 11L, 16L, 2L, 3L,
4L, 5L, 6L, 7L, 10L, 14L), .Label = c("group 1", "group 10",
"group 11", "group 12", "group 13", "group 14", "group 15 ",
"group 16 ", "group 17", "group 18", "group 19", "group 2", "group 20",
"group 21", "group 22", "group 23", "group 24", "group 3", "group 4 ",
"group 5 ", "group 6", "group 7 ", "group 8 ", "group 9 "), class = "factor"),
habitat.type = structure(c(3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L), .Label = c("edge", "forest", "Pasture"), class = "factor"),
species.richness = c(3L, 5L, 2L, 3L, 1L, 2L, 4L, 3L, 9L,
5L, 5L, 4L, 4L, 4L, 8L, 7L, 4L, 3L, 5L, 2L, 3L, 6L, 2L, 1L
), X = c(2.875, 2.875, 2.875, 2.875, 2.875, 2.875, 2.875,
2.875, 5.75, 5.75, 5.75, 5.75, 5.75, 5.75, 5.75, 5.75, 3.25,
3.25, 3.25, 3.25, 3.25, 3.25, 3.25, 3.25), se = c(2.32340059786604,
1.7996983644207, 2.84557296642458, 2.32340059786604, 4.02424788183988,
2.84557296642458, 2.01212394091994, 2.32340059786604, 1.34141596061329,
1.7996983644207, 1.7996983644207, 2.01212394091994, 2.01212394091994,
2.01212394091994, 1.42278648321229, 1.52102272991811, 2.01212394091994,
2.32340059786604, 1.7996983644207, 2.84557296642458, 2.32340059786604,
1.64289231816395, 2.84557296642458, 4.02424788183988)), .Names = c("group.name",
"habitat.type", "species.richness", "X", "se"), row.names = c(NA,
-24L), class = "data.frame")
我究竟做错了什么？我花了一些时间阅读 R 中的误差条，但我没有成功。
ant.d$se <- 1.96*(sd(ant.d$species.richness, na.rm=T)/sqrt(ant.d$species.richness))
p<-ggplot(data = ant.d, aes(y = species.richness, x = habitat.type)) +
geom_bar(stat="identity",position="dodge")
p
p + geom_bar(position=dodge) + geom_errorbar(aes(ymax = species.richness + se, ymin=species.richness - se), position=dodge, width=0.25)
最佳答案
如果我正确理解您要实现的目标，那么最好在绘图之前汇总您的数据:
df <- aggregate(cbind(species.richness,se) ~ habitat.type, ant.d, mean)
ggplot(data = df, aes(x = habitat.type, y = species.richness)) +
geom_bar(stat="identity", fill="grey") +
geom_errorbar(stat="identity", aes(ymax = species.richness + se, ymin=species.richness - se), width=0.25)
这使:
如果您想要每个
habitat.type 中的组，您可以是这样的:ggplot(data = ant.d, aes(x = habitat.type, y = species.richness, fill = group.name)) +
geom_bar(stat="identity", position=position_dodge(0.8)) +
geom_errorbar(stat="identity", aes(ymax = species.richness + se, ymin=species.richness - se), width=0.25,
position=position_dodge(0.8)) +
scale_fill_discrete(guide = guide_legend(ncol=2))
这使:
关于R ggplot2 - 相互分层的误差线，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32644315/