我有两个数据库:

Reservation
------------------------------------------------
| ID | RoomID | RoomName | BookingDate         |
|-----------------------------------------------
| 1  | 77     | Gold     | 2017-12-05 00:00:00 |
| 2  | 88     | Crystal  | 2017-12-11 00:00:00 |
| 3  | 88     | Crystal  | 2017-12-20 00:00:00 |
| 4  | 99     | Diamond  | 2017-12-01 00:00:00 |
| 5  | 77     | Gold     | 2017-12-04 00:00:00 |
| 6  | 77     | Gold     | 2017-12-15 00:00:00 |
-------------------------------------------------

Room
-----------------
| ID | RoomName |
-----------------
| 77 | Gold     |
| 88 | Crystal  |
| 99 | Diamond  |
-----------------


我试图计算日期范围内房间的记录数。假定输出为:


------------------------------------------------------
| Date                    | Gold | Crystal | Diamond |
------------------------------------------------------
| 1.12.2017 - 3.12.2017   |  0   |    0    |   1     |
| 4.12.2017 - 10.12.2017  |  2   |    0    |   0     |
| 11.12.2017 - 17.12.2017 |  1   |    1    |   0     |
| 18.12.2017 - 24.12.2017 |  0   |    1    |   0     |
| 25.12.2017 - 31.12.2017 |  0   |    0    |   0     |
------------------------------------------------------



我的编码如下:

<table>
<tr><th> Date </th>
    <?php
     $sql = mysql_query("SELECT * FROM Room", $con);
     while($record = mysql_fetch_array($sql)) {
    ?>
    <td> <?php echo $record['RoomName']?> </td>
    <?php
     }
    ?>
</tr>
<tr> <td>
     <?php
    $week = date("W", strtotime($_GET['Year'] . "-" . $_GET['Month'] ."-01")); // weeknumber of first day of month
    $startRange = date("d.m.Y", strtotime($_GET['Year'] . "-" . $_GET['Month'] ."-01")); // first day of month
    echo $startRange . " to ";
    $unix = strtotime($_GET['Year']."W".$week ."+1 week");
    while(date("m", $unix) == $_GET['Month']){ // keep looping/output of while it's correct month
        $endRange = date("d.m.Y", $unix-86400);
        echo $endRange . "</td>"; // Sunday of previous week

        //counting for Gold Room
        $res=mysql_query("SELECT * FROM Reservation WHERE (BookingDate>='".$startRange."' AND BookingDate<='".$endRange."') AND RoomID='77' ");
        $count=mysql_num_rows($res);
        echo "<td align='center'>" . $count . "</td>";
        //end counting part

        //counting part Crystal Room
        $res=mysql_query("SELECT * FROM Reservation WHERE (BookingDate>='".$startRange."' AND BookingDate<='".$endRange."') AND RoomID='88' ");
        $count=mysql_num_rows($res);
        echo "<td align='center'>" . $count . "</td>";
        //end counting part

       //counting part Diamond Room
       $res=mysql_query("SELECT * FROM Reservation WHERE (BookingDate>='".$startRange."' AND BookingDate<='".$endRange."') AND RoomID='99' ");
      $count=mysql_num_rows($res);
      echo "<td align='center'>" . $count . "</td>";
      //end counting part

      echo "</tr><tr> <td align='center'>";

      $lastStartRange = date("d.m.Y", $unix);
      echo $lastStartRange ." to "; // this week's monday
      $unix = $unix + (86400*7);
     }

   $lastEndRange = date("t.m.Y", strtotime($_GET['Year'] . "-" . $_GET['Month']));
   echo $lastEndRange; //echo last day of month
   ?>
   </td> <td align="center">
   <?php
   //counting for Gold Room
   $res=mysql_query("SELECT * FROM Reservation WHERE (BookingDate>='".$lastStartRange."' AND BookingDate<='".$lastEndRange."') AND RoomID='77' ");
    $count=mysql_num_rows($res);
    echo "<td align='center'>" . $count . "</td>";
    //end counting part

    //counting part Crystal Room
    $res=mysql_query("SELECT * FROM Reservation WHERE (BookingDate>='".$lastStartRange."' AND BookingDate<='".$lastEndRange."') AND RoomID='88' ");
    $count=mysql_num_rows($res);
    echo "<td align='center'>" . $count . "</td>";
    //end counting part

    //counting part Diamond Room
    $res=mysql_query("SELECT * FROM Reservation WHERE (BookingDate>='".$lastStartRange."' AND BookingDate<='".$lastEndRange."') AND RoomID='99' ");
    $count=mysql_num_rows($res);
    echo "<td align='center'>" . $count . "</td>";
    //end counting part
  ?>





上面代码的问题是,当我选择month = January时,它将显示日期范围01.01.2017-31.12.2017。
至于记录计数,它与Reservation的数据库表中的记录不匹配。我不知道如何简化代码。对我的问题有任何建议或解决方案吗?


$_GET['Month']$_GET['Year']中检索日期范围的月份和年份。日期范围应根据所选的月份和年份动态更改。
日期范围是任何选定月份的星期范围,因此没有固定的星期范围。
表格标题上的房间名称应从
数据库表“ Room”。
计数应计算日期范围内特定房间的预订数量。


谢谢..

最佳答案

好吧,您可以尝试构建以下查询

 SELECT '1.12.2017 - 3.12.2017',
        sum(CASE WHEN room_id = 77 THEN 1 ELSE 0 END) AS Gold,
        sum(CASE WHEN room_id = 88 THEN 1 ELSE 0 END) AS Crystal,
        sum(CASE WHEN room_id = 99 THEN 1 ELSE 0 END) AS Dimond,
FROM Reservations
WHERE BookingDate BETWEEN '2017-12-01 00:00:00' AND '2017-12-03 23:59:59'
UNION
SELECT '4.12.2017 - 10.12.2017',
        sum(CASE WHEN room_id = 77 THEN 1 ELSE 0 END) AS Gold,
        sum(CASE WHEN room_id = 88 THEN 1 ELSE 0 END) AS Crystal,
        sum(CASE WHEN room_id = 99 THEN 1 ELSE 0 END) AS Dimond,
FROM Reservations
WHERE BookingDate BETWEEN '2017-12-04 00:00:00' AND '2017-12-10 23:59:59'
UNION
SELECT '11.12.2017 - 17.12.2017',
        sum(CASE WHEN room_id = 77 THEN 1 ELSE 0 END) AS Gold,
        sum(CASE WHEN room_id = 88 THEN 1 ELSE 0 END) AS Crystal,
        sum(CASE WHEN room_id = 99 THEN 1 ELSE 0 END) AS Dimond,
FROM Reservations
WHERE BookingDate BETWEEN '2017-12-11 00:00:00' AND '2017-12-17 23:59:59'
UNION
SELECT '18.12.2017 - 24.12.2017',
        sum(CASE WHEN room_id = 77 THEN 1 ELSE 0 END) AS Gold,
        sum(CASE WHEN room_id = 88 THEN 1 ELSE 0 END) AS Crystal,
        sum(CASE WHEN room_id = 99 THEN 1 ELSE 0 END) AS Dimond,
FROM Reservations
WHERE BookingDate BETWEEN '2017-12-18 00:00:00' AND '2017-12-24 23:59:59'
UNION
SELECT '25.12.2017 - 31.12.2017 ',
        sum(CASE WHEN room_id = 77 THEN 1 ELSE 0 END) AS Gold,
        sum(CASE WHEN room_id = 88 THEN 1 ELSE 0 END) AS Crystal,
        sum(CASE WHEN room_id = 99 THEN 1 ELSE 0 END) AS Dimond,
FROM Reservations
WHERE BookingDate BETWEEN '2017-12-25 00:00:00' AND '2017-12-31 23:59:59'


您需要使用所需的输出参数来建立这样的查询。这样,您将可以一次获得输出。现在,这里唯一的问题似乎是RoomID和RoomName看起来不是动态的。但是同样,您需要在查询中动态构建它。因此,如果明天要添加另一个房间,它也将出现在查询中。

关于php - 如何计算日期范围内的记录及其条件,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47765166/

10-12 17:25