我有以下数据框:
df <- structure(list(BoneMarrow = c(30, 0, 0, 31138, 2703), Pulmonary = c(3380,
21223.3333333333, 0, 0, 27)), row.names = c("ATP1B1", "CYCS",
"DDX5", "GNB2L1", "PRR11"), class = "data.frame", .Names = c("BoneMarrow",
"Pulmonary"))
df
#> BoneMarrow Pulmonary
#> ATP1B1 30 3380.00
#> CYCS 0 21223.33
#> DDX5 0 0.00
#> GNB2L1 31138 0.00
#> PRR11 2703 27.00
我想做的是摆脱任何列中值
> df %>% filter(!apply(., 1, function(row) any(row <= 8 )))
BoneMarrow Pulmonary
1 30 3380
2 2703 27
如何将其保存在dplyr链中?
最佳答案
您可以将行名称转换为列,并在过滤后返回:
library(dplyr)
library(tibble) # for `rownames_to_column` and `column_to_rownames`
df %>%
rownames_to_column('gene') %>%
filter_if(is.numeric, all_vars(. >= 8)) %>%
column_to_rownames('gene')
# BoneMarrow Pulmonary
# ATP1B1 30 3380
# PRR11 2703 27
关于r - 如何在dplyr链中进行过滤后保留基本数据帧行名,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/45427444/