我有以下数据框:


df <- structure(list(BoneMarrow = c(30, 0, 0, 31138, 2703), Pulmonary = c(3380,
21223.3333333333, 0, 0, 27)), row.names = c("ATP1B1", "CYCS",
"DDX5", "GNB2L1", "PRR11"), class = "data.frame", .Names = c("BoneMarrow",
"Pulmonary"))

df
#>        BoneMarrow Pulmonary
#> ATP1B1         30   3380.00
#> CYCS            0  21223.33
#> DDX5            0      0.00
#> GNB2L1      31138      0.00
#> PRR11        2703     27.00

我想做的是摆脱任何列中值
> df %>% filter(!apply(., 1, function(row) any(row <= 8 )))
  BoneMarrow Pulmonary
1         30      3380
2       2703        27

如何将其保存在dplyr链中?

最佳答案

您可以将行名称转换为列,并在过滤后返回:

library(dplyr)
library(tibble)  # for `rownames_to_column` and `column_to_rownames`

df %>%
    rownames_to_column('gene') %>%
    filter_if(is.numeric, all_vars(. >= 8)) %>%
    column_to_rownames('gene')

#        BoneMarrow Pulmonary
# ATP1B1         30      3380
# PRR11        2703        27

关于r - 如何在dplyr链中进行过滤后保留基本数据帧行名,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/45427444/

10-12 17:23