c - C分割字串

#include "stdio.h"
#include "string.h"
#include "stdlib.h"

char *strArray[40];

void parsing(char *string){
  int i = 0;
  char *token = strtok(string, " ");
  while(token != NULL)
  {
    strcpy(strArray[i], token);
    printf("[%s]\n", token);
    token = strtok(NULL, " ");
    i++;
  }
}

int main(int argc, char const *argv[]) {
char *command = "This is my best day ever";
parsing(command); //SPLIT WITH " " put them in an array - etc array[0] = This , array[3] = best

return 0;
}

这是我的代码，有什么简单的解决方法吗？顺便说一下，我的代码不起作用。我是C语言的新手，我不知道如何处理它：（帮助

最佳答案

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *strArray[40];

void parsing(const char *string){//Original does not change
    int i = 0;
    strArray[i++] = strdup(string);//make copy to strArray[0]

    char *token = strtok(*strArray, " ");
    while(token != NULL && i < 40 - 1){
        strArray[i++] = token;
        //printf("[%s]\n", token);
        token = strtok(NULL, " ");
    }
    strArray[i] = NULL;//Sentinel

}

int main(void){
    char *command = "This is my best day ever";
    parsing(command);

    int i = 1;
    while(strArray[i]){
        printf("%s\n", strArray[i++]);
    }
    free(strArray[0]);
    return 0;
}

int parsing(char *string){//can be changed
    int i = 0;

    char *token = strtok(string, " ");
    while(token != NULL && i < 40){
        strArray[i] = malloc(strlen(token)+1);//Ensure a memory for storing
        strcpy(strArray[i], token);
        token = strtok(NULL, " ");
        i++;
    }
    return i;//return number of elements
}

int main(void){
    char command[] = "This is my best day ever";
    int n = parsing(command);

    for(int i = 0; i < n; ++i){
        printf("%s\n", strArray[i]);
        free(strArray[i]);
    }
    return 0;
}

关于c - C分割字串，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/35659308/