我像这样遍历一个数组。
NSArray *array = [[currentRaum raumattribute] allObjects];
NSString *compositeString = [ [ NSString alloc ] init ];
for( Raumattribute *attr in array ){
compositeString = [ NSString stringWithFormat:@"%@ %@",compositeString, attr.attributname ];
[raumAttributLabel setText:compositeString];
我想要这样的输出---->猫,狗,老鼠
但是,如果我这样做:
compositeString = [ NSString stringWithFormat:@"%@ %@,",compositeString, attr.attributname ];
输出是Cat,Dog,Mouse,
或者,如果我这样做:
compositeString = [ NSString stringWithFormat:@"%@ ,%@",compositeString, attr.attributname ];
输出其,Cat,Dog,Mouse
有解决方案吗?
最佳答案
您可以使用数组的valueForKey:
和componentsJoinedByString:
方法做到这一点:
NSString * compositeString = [[array valueForKey:@"attributname"] componentsJoinedByString:@","]
valueForKey:
将为每个数组元素创建属性名称值数组componentsJoinedByString:
将这些值合并为一个字符串,并以逗号分隔关于ios - 以“,”分隔吗?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/10282597/