我正在尝试使用模板编写一些代码,现在已经尝试了几个小时,但仍然无法解决此错误:14 C:\Users\urielbertoche\Desktop\main.cpp request for member 'defineConstante' in 'planilhaTeste', which is of non-class type 'planilha<double> ()()'
我目前的主要想法是:
int main (){
planilha<double> planilhaTeste();
unsigned int contador=0;
double number=0;
for(contador=0; contador<5; contador++)
{
cout<<"Escreva a constante para a celula "<<contador<<endl;
cin>>number;
planilhaTeste.defineConstante(contador, number); // this is line 14 by the way
planilhaTeste->primeiro=planilhaTeste->primeiro->prox;
cout<<planilhaTeste.termoConstante;
}
return 0;
}
所有的包含物都已经制作好了,我的标题是:
template <class Type>
class planilha{
protected:
struct celula{
double termoConstante;
Type resultadoFinal;
lista termos;
int numCelula;
celula *prox;
celula():prox(NULL){};
celula(double novoTermo, int numCel, celula *proxElo=NULL):termoConstante(novoTermo),
resultadoFinal(novoTermo), numCelula(numCel), prox(proxElo), termos(){};
};
celula *primeiro;
public:
planilha();
planilha(const planilha<Type>& origem);
~planilha(void);
planilha<Type> operator=(const planilha<Type>& origem);
void defineConstante(int numCel, const Type& valor);
bool insere_termo(unsigned int numCel, unsigned int refCel, double fator);
void apagar(unsigned int num_cel);
};
并且功能代码为:
template <class Type>
void planilha<Type>::defineConstante(int numCel, const Type& valor){
celula * finder = primeiro;
while(finder!=NULL){
if(this->numCelula==numCel){
this->termoConstante = valor;
return;
}
finder=finder->prox;
}
}
我真的不知道为什么会发生此错误。谁能帮我?谢谢。
最佳答案
planilha<double> planilhaTeste();
该行声明了一个planilhaTeste函数,该函数返回planilha ,而不是planilha 类型的变量。只要您需要此处的默认ctor,只需从声明中删除空括号即可:planilha<double> planilhaTeste;
关于c++ - 尝试构建基于模板的代码时出错,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7868347/