我正在为Chrome扩展程序,我需要将活动标签的网址传递给包含php代码的文件。我的manifest.json代码:
{ "name": "demo",
"version": "1.0",
"manifest_version": 2,
"description": "Making your first Google Chrome extension.",
"browser_action": {
"default_icon": "icon.png",
"default_popup": "chrome.html"
},
"permissions": [
"http://www.mysite.com/",
"tabs"
]
}
和AJAX代码:
window.onload = function() {
var XHR = new XMLHttpRequest;
chrome.tabs.query({active:true,currentWindow:true},
function(tab){tabUrl = tab.url;});
XHR.open('GET', 'http://www.mysite.com/chrome/chrome.php?tab='+tabUrl+'', true);
XHR.onreadystatechange = function () {
if (4 == this.readyState) {
var status = this.status;
if (400 > status) {
var responseText = this.responseText;
if (responseText) {
document.getElementById('resultado').innerHTML = responseText;
}
}
}
};
XHR.send();
}
感谢帮助。
最佳答案
我认为您应该这样做,因为在代码中,因为XHR.send();时tabs.query是异步的。获取执行tabUrl尚未设置。
window.onload = function() {
var XHR = new XMLHttpRequest;
chrome.tabs.query({
active: true,
currentWindow: true
}, function(tab) {
tabUrl = tab.url;
XHR.open('GET', 'http://www.mysite.com/chrome/chrome.php?tab=' + tabUrl + '', true);
XHR.onreadystatechange = function() {
if(4 == this.readyState) {
var status = this.status;
if(400 > status) {
var responseText = this.responseText;
if(responseText) {
document.getElementById('resultado').innerHTML = responseText;
}
}
}
};
XHR.send();
});
}
关于javascript - chrome事件标签网址传递到php文件,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13406511/