c - C中的字符计数程序

字符数的输出是实际的数字加3。
我不知道为什么？
这是代码：

void main(void)
{

 int ch,w=0,c=0;
 do
 {
  ch=getche();
  ++c;
  if(ch==32)
  {
      ++w;
      ++c;
  }

 }while(ch!=13);
 printf("\nnum of characters is  %d",c);
 printf("\nnum of words is  %d",w);
        getch();
}

最佳答案

void main(void)
{
    int ch,w=0,c=0,lastch=32;
    while((ch = getche()) != 13) //get input and check if it's ENTER key
    {
        ++c;
        if(ch == 32 && lastch != ch) //make sure two continuous spaces are not counted as a word as pointed out by paxdiablo
            ++w;
        lastch = ch;
    }
    if(lastch != 32) //for a word with no space
        ++w;
    printf("\nnum of characters is  %d",c);
    printf("\nnum of words is  %d",w);
    getch();
}

您可以考虑使用char而不是int。

关于c - C中的字符计数程序，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/2849716/