如何使SQL Fiddle从GROUP by返回的元素子集中获得结果?
桌子
CREATE TABLE IF NOT EXISTS `accounts` (
`master_id` int(3) unsigned NOT NULL,
`child_id` int(3) unsigned NOT NULL,
`name` varchar(200) NOT NULL
);
数据
INSERT INTO `accounts` (`master_id`, `child_id`, `name`) VALUES
('222', '555', 'child_555'),
('111', '111', 'master_111'),
('111', '999', 'child_999'),
('111', '888', 'child_888'),
('222', '222', 'master_222'),
('222', '777', 'child_777'),
('111', '666', 'child_666');
当前查询
SELECT
master_id,
name,
count(*) as "Total Accounts"
FROM `accounts`
GROUP BY master_id ASC;
结果
+-----------+------------+-------+
| master_id | name | Total |
+-----------+------------+-------+
| 111 | master_111 | 4 |
| 222 | child_555 | 3 |
+-----------+------------+-------+
预期
- Don't count child if child_id == master_id
- Get correct name
+-----------+------------+-------+
| master_id | name | Total |
+-----------+------------+-------+
| 111 | master_111 | 3 |
| 222 | master_222 | 2 |
+-----------+------------+-------+
最佳答案
我认为使用一些条件逻辑进行简单的聚合是最好的方法:
SELECT master_id,
MAX(CASE WHEN child_id = master_id THEN name END) as name,
SUM(child_id <> master_id) as "Total Accounts"
FROM `accounts`
GROUP BY master_id ASC;
Here是这个的SQL小提琴。
关于mysql - 从一组中选择值,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/50484699/