android - ParseQueryAdapter，不显示结果

我试图在我的项目中使用ParseQueryAdapter，并且没有任何运气来显示结果。

我的目标是从ParseUser获取数据。因此，我的模型扩展了ParseUser：

所以我有一个模型：

@ParseClassName("Midwifefirm")
public class Midwifefirm extends ParseUser {



    public Midwifefirm() {
        // A default constructor is required.
    }

    //practice name
    public String getPracticeName() {
        return getString("practicename");
    }

    public void setPracticeName(String title) {
        put("title", title);
    }

    //education

    public String getEducation() {
        return getString("education");
    }

    public void setEducation(String education) {
        put("education", education);
    }

    //years in practice

    public String getYearsinPractice() {
        return getString("yearsinpractice");
    }

    public void setYearsinPractice(String yearsinpractice) {
        put("yearsinpractice", yearsinpractice);
    }

    //practice philosophy

    public String getPracticePhilosophy() {
        return getString("practicephilosophy");
    }

    public void setPracticePhilosophy(String practicephilosophy) {
        put("practicephilosophy", practicephilosophy);
    }

适配器在这里；我认为问题可能出在我的查询中：

public class CustomMidwifeAdapter extends ParseQueryAdapter<Midwifefirm> {


    public CustomMidwifeAdapter(Context context) {
        //query using Midwifefirm class, to get list of midwives
        super(context, new ParseQueryAdapter.QueryFactory<Midwifefirm>() {
            public ParseQuery<Midwifefirm> create() {

                ParseQuery query = new ParseQuery("Midwifefirm");
                query.whereEqualTo("userType", "midwife");


                return query;

            }


        });

    }

    @Override
    public View getItemView(Midwifefirm midwifefirm, View view, ViewGroup parent) {

        if (view == null) {
            view = View.inflate(getContext(), R.layout.activity_midwife_result_list, null);

        }

        //use midwifefirm as item view/list

        super.getItemView(midwifefirm, view, parent);


        // find in layout the practice name
        TextView titleTextView = (TextView) view.findViewById(R.id.practicename);

        //in the midwifefirm data model, call getPracticename
        titleTextView.setText(midwifefirm.getPracticeName());

        // Add education view
        TextView EducationView = (TextView) view.findViewById(R.id.education);

        EducationView.setText(midwifefirm.getEducation());

        // Add yearsexperience view
        TextView ExperienceView = (TextView) view.findViewById(R.id.yearsinpractice);
        ExperienceView.setText(midwifefirm.getYearsinPractice());

        //Add practice philosophy view
        TextView PracticePhilosophyView = (TextView) view.findViewById(R.id.practicephilosophy);
        PracticePhilosophyView.setText(midwifefirm.getPracticePhilosophy());


        return view;
    }

}

这是我的ListView；

public class MidwifeResultList extends ListActivity {


    private ParseQueryAdapter<Midwifefirm> mainAdapter;

    private CustomMidwifeAdapter midwifeListAdapter;



    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        //set display to listview, empty
        getListView().setClickable(false);




        //initialize main ParseQueryAdapter
        mainAdapter = new ParseQueryAdapter<Midwifefirm>(this, Midwifefirm.class);
        mainAdapter.setTextKey("practicename");
        mainAdapter.setTextKey("education");
        mainAdapter.setTextKey("yearsinpractice");
        mainAdapter.setTextKey("practicephilosophy");


        // Initialize the subclass of ParseQueryAdapter
        midwifeListAdapter = new CustomMidwifeAdapter(this);


        setListAdapter(mainAdapter);

        // Initialize ListView and set initial view to mainAdapter
       // listView = (ListView) findViewById(R.id.lvMidwives);
      //  listView.setAdapter(mainAdapter);
      //  mainAdapter.loadObjects();

    }





}

我可能将其设置为错误..感谢您的任何见识。

最佳答案

仅查看您提供的内容，我认为这与您的查询有关。您正在查询键“ userType”，但子类Midwifefirm似乎没有该键。

编辑

要回答您的评论，您将使用以下查询获取所有助产士对象：

ParseQuery<Midwifefirm> query = ParseQuery.getQuery(Midwifefirm.class);
/* add any additional constraints to your query here */
query.findInBackground(new FindCallback<Midwifefirm>() {
    @Override
    public void done(List<Midwifefirm> results, ParseException e) {

    }
}

我相信Parse对单个查询100可以获取的对象数量有一定的限制，因此您可能必须研究增加方法来满足需求的方法。

关于android - ParseQueryAdapter，不显示结果，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/29974952/